To start you off on your assignment, String.split splits strings on a regular expression and this expression may be an empty string: String[] ary = “abc”.split(“”); Yields the array: (java.lang.String[]) [, a, b, c] Getting rid of the empty 1st entry is left as an exercise for the reader 🙂 Note: In Java 8, the … Read more
This stratify parameter makes a split so that the proportion of values in the sample produced will be the same as the proportion of values provided to parameter stratify. For example, if variable y is a binary categorical variable with values 0 and 1 and there are 25% of zeros and 75% of ones, stratify=y … Read more
Change this… var string = document.location; to this… var string = document.location + ”; This is because document.location is a Location object. The default .toString() returns the location in string form, so the concatenation will trigger that. You could also use document.URL to get a string.
You need the put the characters you wish to split on in a character class, which tells the regular expression engine “any of these characters is a match”. For your purposes, this would look like: date.split(/[.,\/ -]/) Although dashes have special meaning in character classes as a range specifier (ie [a-z] means the same as … Read more
Several alternatives: 1) two ways with data.table: library(data.table) # method 1 (preferred) setDT(v)[, lapply(.SD, function(x) unlist(tstrsplit(x, “,”, fixed=TRUE))), by = AB ][!is.na(director)] # method 2 setDT(v)[, strsplit(as.character(director), “,”, fixed=TRUE), by = .(AB, director) ][,.(director = V1, AB)] 2) a dplyr / tidyr combination: library(dplyr) library(tidyr) v %>% mutate(director = strsplit(as.character(director), “,”)) %>% unnest(director) 3) with … Read more
“cat”.split(“(?!^)”) This will produce array [“c”, “a”, “t”]
A naive algorithm won’t give good results when applied to real-world data. Here is a 20-line algorithm that exploits relative word frequency to give accurate results for real-word text. (If you want an answer to your original question which does not use word frequency, you need to refine what exactly is meant by “longest word”: … Read more
Here’s the regex one-liner version: System.out.println(Arrays.toString( “Thequickbrownfoxjumps”.split(“(?<=\\G.{4})”) )); \G is a zero-width assertion that matches the position where the previous match ended. If there was no previous match, it matches the beginning of the input, the same as \A. The enclosing lookbehind matches the position that’s four characters along from the end of the last … Read more
You should parse newlines regardless of the platform (operation system) This split is universal with regular expressions. You may consider using this: var ks = $(‘#keywords’).val().split(/\r?\n/); E.g. “a\nb\r\nc\r\nlala”.split(/\r?\n/) // [“a”, “b”, “c”, “lala”]
I suggest l = re.compile(“(?<!^)\s+(?=[A-Z])(?!.\s)”).split(s) Check this demo.