Concatenating the querysets into a list is the simplest approach. If the database will be hit for all querysets anyway (e.g. because the result needs to be sorted), this won’t add further cost. from itertools import chain result_list = list(chain(page_list, article_list, post_list)) Using itertools.chain is faster than looping each list and appending elements one by … Read more
If you want to find all commits where the commit message contains a given word, use $ git log –grep=word If you want to find all commits where “word” was added or removed in the file contents (to be more exact: where the number of occurrences of “word” changed), i.e., search the commit contents, use … Read more
Depending on the exact string you’re searching, the \V prefix will probably do the trick. See :help \V: after: \v \m \M \V matches ~ ‘magic’ ‘nomagic’ $ $ $ \$ matches end-of-line . . \. \. matches any character * * \* \* any number of the previous atom () \(\) \(\) \(\) grouping … Read more
Once you are in scrollback mode with Ctrl + A, ESC, you should be able to search backwards through the buffer as described in the manual. So to search for the word “string”, press Ctrl + A, ESC, enter ?string and press Enter. It will take you backwards through the buffer to the word string. … Read more
Also note that the list of values I’ll have won’t have duplicate data and I don’t actually care about the order it’s in; I just need to be able to check for the existence of a value. Don’t use a list, use a set() instead. It has exactly the properties you want, including a blazing … Read more
To sort files by date: import glob import os files = glob.glob(“*cycle*.log”) files.sort(key=os.path.getmtime) print(“\n”.join(files)) See also Sorting HOW TO.
You can do something like this: $(‘#searchString’).keyup(function(e) { clearTimeout($.data(this, ‘timer’)); if (e.keyCode == 13) search(true); else $(this).data(‘timer’, setTimeout(search, 500)); }); function search(force) { var existingString = $(“#searchString”).val(); if (!force && existingString.length < 3) return; //wasn’t enter, not > 2 char $.get(‘/Tracker/Search/’ + existingString, function(data) { $(‘div#results’).html(data); $(‘#results’).show(); }); } What this does is perform a … Read more
The simpelst way would be to compare each element: public int indexOf(byte[] outerArray, byte[] smallerArray) { for(int i = 0; i < outerArray.length – smallerArray.length+1; ++i) { boolean found = true; for(int j = 0; j < smallerArray.length; ++j) { if (outerArray[i+j] != smallerArray[j]) { found = false; break; } } if (found) return i; … Read more
The scoring contains the Inverse Document Frequency(IDF). If the term “John Smith” is in one partition, 0, 100 times and in partition 1, once. The score for searching for John Smith would be higher search in partition 1 as the term is more scarce. To get round this you would wither have to have your … Read more