replace

Find and Replace Values in XML using Python

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The basics: from xml.etree import ElementTree as et tree = et.parse(datafile) tree.find(‘idinfo/timeperd/timeinfo/rngdates/begdate’).text=”1/1/2011″ tree.find(‘idinfo/timeperd/timeinfo/rngdates/enddate’).text=”1/1/2011″ tree.write(datafile) You can shorten the path if the tag name is unique. This syntax finds the first node at any depth level in the tree. tree.find(‘.//begdate’).text=”1/1/2011″ tree.find(‘.//enddate’).text=”1/1/2011″ Also, read the documentation, esp. the XPath support for locating nodes.

String replace a Backslash

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sSource = sSource.replace(“\\/”, “https://stackoverflow.com/”); String is immutable – each method you invoke on it does not change its state. It returns a new instance holding the new state instead. So you have to assign the new value to a variable (it can be the same variable) replaceAll(..) uses regex. You don’t need that.

Stop cursor from jumping to end of input field in javascript replace

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In addition to gilly3’s answer, I thought someone might find it useful to see an actual code snippet. In the example below, the selectionStart property is retrieved from the input element prior to the JavaScript string manipulation. Then selectionStart is set back to the initial position after the manipulation. Depending on what you’re trying to … Read more

c# replace \” characters

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Were you trying it like this: string text = GetTextFromSomewhere(); text.Replace(“\\”, “”); text.Replace(“\””, “”); ? If so, that’s the problem – Replace doesn’t change the original string, it returns a new string with the replacement performed… so you’d want: string text = GetTextFromSomewhere(); text = text.Replace(“\\”, “”).Replace(“\””, “”); Note that this will replace each backslash … Read more

Java Replace Character At Specific Position Of String? [duplicate]

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Petar Ivanov’s answer to replace a character at a specific index in a string question String are immutable in Java. You can’t change them. You need to create a new string with the character replaced. String myName = “domanokz”; String newName = myName.substring(0,4)+’x’+myName.substring(5); Or you can use a StringBuilder: StringBuilder myName = new StringBuilder(“domanokz”); myName.setCharAt(4, … Read more

search and replace value in PHP array

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Instead of a function that only replaces occurrences of one value in an array, there’s the more general array_map: array_map(function ($v) use ($value, $replacement) { return $v == $value ? $replacement : $v; }, $arr); To replace multiple occurrences of multiple values using array of value => replacement: array_map(function ($v) use ($replacement) { return isset($replacement[$v]) … Read more