Android: can’t replace one fragment with another
You cannot replace a fragment defined statically in the layout file. You can only replace fragments that you added dynamically via a FragmentTransaction.
You cannot replace a fragment defined statically in the layout file. You can only replace fragments that you added dynamically via a FragmentTransaction.
This is a state-of-the-union answer as of Windows PowerShell v5.1 / PowerShell Core v6.2.0: Andrew Savinykh’s ill-fated answer, despite being the accepted one, is, as of this writing, fundamentally flawed (I do hope it gets fixed – there’s enough information in the comments – and in the edit history – to do so). Ansgar Wiecher’s … Read more
A simple option is to check for matches before you replace: var regex = /i/g; var newStr = str; var replaced = str.search(regex) >= 0; if(replaced){ newStr = newStr.replace(regex, ‘!’); } If you don’t want that either, you can abuse the replace callback to achieve that in a single pass: var replaced = false; var … Read more
You need to set the text after the replace call: $(‘.element span’).each(function() { console.log($(this).text()); var text = $(this).text().replace(‘N/A, ‘, ”); $(this).text(text); }); <script src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js”></script> <div class=”element”> <span>N/A, Category</span> </div> Here’s another cool way you can do it (hat tip @Felix King): $(“.element span”).text(function(index, text) { return text.replace(“N/A, “, “”); });
I believe you want :%s/foo\(\w\+\)Bar/& = \1 + \1\Old/ explanation: \w\+ finds one or more occurences of a character. The preceeding foo and following Bar ensure that these matched characters are just between a foo and a Bar. \(…\) stores this characters so that they can be used in the replace part of the substitution. … Read more
Use the Jinja trim filter: “{{ lookup(‘file’, ‘foo.xml’ ) | trim }}”
Using regular expression function re.sub to replace words at end of string import re s = “123123” s = re.sub(’23$’, ‘penguins’, s) print s Prints: 1231penguins or import re s = “123123” s = re.sub(‘^12’, ‘penguins’, s) print s Prints: penguins3123
A somewhat inefficient way of doing this: NSString *s = @”foo/bar:baz.foo”; NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@”/:.”]; s = [[s componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @””]; NSLog(@”%@”, s); // => foobarbazfoo Look at NSScanner and -[NSString rangeOfCharacterFromSet: …] if you want to do this a bit more efficiently.
You did not assign it to test. Strings are immutable. test = test.replace(“KP”, “”); You need to assign it back to test.