In [21]: df = pd.DataFrame([(1,2,3), (‘foo’,’bar’,’baz’), (4,5,6)]) In [22]: df Out[22]: 0 1 2 0 1 2 3 1 foo bar baz 2 4 5 6 Set the column labels to equal the values in the 2nd row (index location 1): In [23]: df.columns = df.iloc[1] If the index has unique labels, you can drop … Read more
Copied from http://exampledepot.8waytrips.com/egs/java.io/RenameFile.html // File (or directory) with old name File file = new File(“oldname”); // File (or directory) with new name File file2 = new File(“newname”); if (file2.exists()) throw new java.io.IOException(“file exists”); // Rename file (or directory) boolean success = file.renameTo(file2); if (!success) { // File was not successfully renamed } To append to … Read more
Smaller still I quite like: rename ‘y/A-Z/a-z/’ * On case insensitive filesystems such as OS X’s HFS+, you will want to add the -f flag: rename -f ‘y/A-Z/a-z/’ *
The rename method takes a dictionary for the index which applies to index values. You want to rename to index level’s name: df.index.names = [‘Date’] A good way to think about this is that columns and index are the same type of object (Index or MultiIndex), and you can interchange the two via transpose. This … Read more
No! There is no command which will change the name of all files generated using the component create command. So created ts, html, css/scss, .spec.ts files need to be manually renamed/edited. I am a frequent user of angular cli and I think this would be a nice-to-have command as some time we just create angular … Read more
data.rename(columns={‘gdp’:’log(gdp)’}, inplace=True) The rename show that it accepts a dict as a param for columns so you just pass a dict with a single entry. Also see related
There are many ways to do that: Option 1. Using selectExpr. data = sqlContext.createDataFrame([(“Alberto”, 2), (“Dakota”, 2)], [“Name”, “askdaosdka”]) data.show() data.printSchema() # Output #+——-+———-+ #| Name|askdaosdka| #+——-+———-+ #|Alberto| 2| #| Dakota| 2| #+——-+———-+ #root # |– Name: string (nullable = true) # |– askdaosdka: long (nullable = true) df = data.selectExpr(“Name as name”, “askdaosdka as … Read more
There are several ways, but using rename will probably be the easiest. Using one version of rename: rename ‘s/^fgh/jkl/’ fgh* Using another version of rename (same as Judy2K’s answer): rename fgh jkl fgh* You should check your platform’s man page to see which of the above applies.
Try to use a loop, let, and printf for the padding: a=1 for i in *.jpg; do new=$(printf “%04d.jpg” “$a”) #04 pad to length of 4 mv -i — “$i” “$new” let a=a+1 done using the -i flag prevents automatically overwriting existing files, and using — prevents mv from interpreting filenames with dashes as options.
As mentioned, delete the old one on GitHub and re-push, though the commands used are a bit more verbose than necessary: git push origin :name_of_the_old_branch_on_github git push origin new_name_of_the_branch_that_is_local Dissecting the commands a bit, the git push command is essentially: git push <remote> <local_branch>:<remote_branch> So doing a push with no local_branch specified essentially means “take … Read more