This worked for me Run pyinstaller and stop it to generate the spec file : pyinstaller filename.py A file with .spec as extension should be generated Now add the following lines to the beginning of the spec file : import sys sys.setrecursionlimit(5000) Now run the spec file using : pyinstaller filename.spec
The problem was not with the recursion. Your function did call itself recursively, it just didn’t yield values outside. When you call helper(), you get an iterator as a return value, but you wanted the iterated values of that iterator to be yielded. If you want to yield recursively, you need to yield *. Try … Read more
You can use recursion to explore every “branch” that emerges when every possible letter containing the proper initial character is added to a running list: words = [‘giraffe’, ‘elephant’, ‘ant’, ‘tiger’, ‘racoon’, ‘cat’, ‘hedgehog’, ‘mouse’] def get_results(_start, _current, _seen): if all(c in _seen for c in words if c[0] == _start[-1]): yield _current else: for … Read more
Let’s write a function that returns all permutations of a string as an array. As you don’t want any global variables, returning the permutations is crucial. function permut(string) { if (string.length < 2) return string; // This is our break condition var permutations = []; // This array will hold our permutations for (var i … Read more
List has the flatten method. Why not use it? List(List(1,2), List(3,4)).flatten > List(1,2,3,4)
Since OTP 17.0 there are named funs: 1> Perms = fun F([]) -> [[]]; F(L) -> [[H|T] || H <- L, T <- F(L–[H])] end. #Fun<erl_eval.30.54118792> 2> Perms([a,b,c]). [[a,b,c],[a,c,b],[b,a,c],[b,c,a],[c,a,b],[c,b,a]] Before that you could do this with a little argument trick: 1> Foo = fun(F, X) -> F(F, X) end. #Fun<erl_eval.12.113037538> 2> Foo(Foo, a). <…infinite loop!> … Read more
Here’s an extension that might help. It will traverse all nodes in your hierarchy of objects and pick out the ones that match a criteria. It assumes that each object in your hierarchy has a collection property that holds its child objects. Here’s the extension: /// Traverses an object hierarchy and return a flattened list … Read more
This should solve your problem: import static groovy.io.FileType.FILES new File(‘.’).eachFileRecurse(FILES) { if(it.name.endsWith(‘.groovy’)) { println it } } eachFileRecurse takes an enum FileType that specifies that you are only interested in files. The rest of the problem is easily solved by filtering on the name of the file. Might be worth mentioning that eachFileRecurse normally recurses … Read more
You could write a little, very simple routine that does it, without using a regular expression: Set a position counter pos so that is points to just before the opening bracket after your for or while. Set an open brackets counter openBr to 0. Now keep incrementing pos, reading the characters at the respective positions, … Read more
Why can’t Java use the same approach ? I can’t say which approach will be used, but it’s better-explained in Project Loom’s proposal: As adding the ability to manipulate call stacks to the JVM will undoubtedly be required, it is also the goal of this project to add an even lighter-weight construct that will allow … Read more