How to check an IP address is within a range of two IPs in PHP?
With ip2long() it’s easy to convert your addresses to numbers. After this, you just have to check if the number is in range: if ($ip <= $high_ip && $low_ip <= $ip) { echo “in range”; }
With ip2long() it’s easy to convert your addresses to numbers. After this, you just have to check if the number is in range: if ($ip <= $high_ip && $low_ip <= $ip) { echo “in range”; }
You must be using Python 3. In Python 2, the objects zip and range did behave as you were suggesting, returning lists. They were changed to generator-like objects which produce the elements on demand rather than expand an entire list into memory. One advantage was greater efficiency in their typical use-cases (e.g. iterating over them). … Read more
Use for final selected value: $(“.slider”).on(“change”, function(){console.log(this.value)}); Use to get incremental value as sliding: $(“.slider”).on(“input”, function(){console.log(this.value)});
Use Skip then Take. yourEnumerable.Skip(4).Take(3).Select( x=>x ) (from p in intList.Skip(x).Take(n) select p).sum()
Just define the variable as a variant, and make them equal: Dim DirArray As Variant DirArray = Range(“a1:a5”).Value No need for the Array command.
The range objects are special: Python will compare range objects as Sequences. What that essentially means is that the comparison doesn’t evaluate how they represent a given sequence but rather what they represent. The fact that the start, stop and step parameters are completely different plays no difference here because they all represent an empty … Read more
You can use any of these: # Create a range that does not contain 50 for i in [x for x in xrange(100) if x != 50]: print i # Create 2 ranges [0,49] and [51, 100] (Python 2) for i in range(50) + range(51, 100): print i # Create a iterator and skip 50 … Read more
For large arrays, a vectorised numpy operation is the fastest. If you must loop, prefer xrange/range and avoid using np.arange. In numpy you should use combinations of vectorized calculations, ufuncs and indexing to solve your problems as it runs at C speed. Looping over numpy arrays is inefficient compared to this. (Something like the worst … Read more
Tested your 3 ways with a 1000000-times-loop. t1_test1: ($val >= $min && $val <= $max): 0.3823 ms t2_test2: (in_array($val, range($min, $max)): 9.3301 ms t3_test3: (max(min($var, $max), $min) == $val): 0.7272 ms T1 was fastest, it was basicly this: function t1($val, $min, $max) { return ($val >= $min && $val <= $max); }
In Ruby 1.9.2 === doesn’t work, I get an error: irb(main):019:0> (Time.now .. (Time.now+1)) === Time.now TypeError: can’t iterate from Time from (irb):19:in `each’ from (irb):19:in `include?’ from (irb):19:in `include?’ from (irb):19:in `===’ from (irb):19 from /opt/ruby192/bin/irb:12:in `<main>’ Instead use #cover?: irb(main):002:0> (Time.now..Time.now+4).cover?(Time.now) => true irb(main):003:0> (Time.now..Time.now+4).cover?(Time.now+10) => false