You can use the “pattern-match” operator ~=: if 200 … 299 ~= statusCode { print(“success”) } Or a switch-statement with an expression pattern (which uses the pattern-match operator internally): switch statusCode { case 200 … 299: print(“success”) default: print(“failure”) } Note that ..< denotes a range that omits the upper value, so you probably want … Read more
Off the top of my head, no. I think the best you could do is something like this: def loop(f,n): for i in xrange(n): f() loop(lambda: <insert expression here>, 5) But I think you can just live with the extra i variable. Here is the option to use the _ variable, which in reality, is … Read more
You can just construct a list from the range object: my_list = list(range(1, 1001)) This is how you do it with generators in python2.x as well. Typically speaking, you probably don’t need a list though since you can come by the value of my_list[i] more efficiently (i + 1), and if you just need to … Read more
Let’s say you want to scale a range [min,max] to [a,b]. You’re looking for a (continuous) function that satisfies f(min) = a f(max) = b In your case, a would be 1 and b would be 30, but let’s start with something simpler and try to map [min,max] into the range [0,1]. Putting min into … Read more
The idiomatic approach in Go is to write a for loop like this. for i := 1; i <= 10; i++ { fmt.Println(i) } There’s definitely advantages in ranges and they’re used in many other languages, but a Go design principle is to only introduce an abstraction if the benefits significantly outweigh the costs (including … Read more
range() and xrange() take a third parameter that specifies a step. So you can do the following. range(10, 0, -1) Which gives [10, 9, 8, 7, 6, 5, 4, 3, 2, 1] But for iteration, you should really be using xrange instead. So, xrange(10, 0, -1) Note for Python 3 users: There are no separate … Read more
The map method takes an enumerable object and a block, and runs the block for each element, outputting each returned value from the block (the original object is unchanged unless you use map!): [1, 2, 3].map { |n| n * n } #=> [1, 4, 9] Array and Range are enumerable types. map with a … Read more
You have pylab.ylim: pylab.ylim([0,1000]) Note: The command has to be executed after the plot! Update 2021 Since the use of pylab is now strongly discouraged by matplotlib, you should instead use pyplot: from matplotlib import pyplot as plt plt.ylim(0, 100) #corresponding function for the x-axis plt.xlim(1, 1000)
What does it mean for the ranges to overlap? It means there exists some number C which is in both ranges, i.e. x1 <= C <= x2 and y1 <= C <= y2 To avoid confusion, considering the ranges are: [x1:x2] and [y1:y2] Now, if we are allowed to assume that the ranges are well-formed … Read more
vector<T>::const_iterator first = myVec.begin() + 100000; vector<T>::const_iterator last = myVec.begin() + 101000; vector<T> newVec(first, last); It’s an O(N) operation to construct the new vector, but there isn’t really a better way.