Reading through the manual for Directory Names, you’ll find the answer: Given a directory name, you can combine it with a relative file name using concat: (concat dirname relfile) Be sure to verify that the file name is relative before doing that. If you use an absolute file name, the results could be syntactically invalid … Read more
To be even more pedantic, the most python doc consistent answer would be: mypath = os.path.join(‘c:’, os.sep, ‘sourcedir’) Since you also need os.sep for the posix root path: mypath = os.path.join(os.sep, ‘usr’, ‘lib’)
Path.GetFileName Returns the file name and extension of a file path that is represented by a read-only character span. Path.GetFileNameWithoutExtension Returns the file name without the extension of a file path that is represented by a read-only character span. The Path class is wonderful.
Use os.path.normpath, then os.path.basename: >>> os.path.basename(os.path.normpath(‘/folderA/folderB/folderC/folderD/’)) ‘folderD’ The first strips off any trailing slashes, the second gives you the last part of the path. Using only basename gives everything after the last slash, which in this case is ”.