When you look at the IL-code that those two snippets produce, you’ll realize that VB.NET first converts the integer values to doubles, applies the division and then rounds the result before it’s converted back to int32 and stored in y. C# does none of that. VB.NET IL Code: IL_0000: ldc.i4.s 10 IL_0002: stloc.1 IL_0003: ldc.i4.s … Read more
To be pedantic, the C specification does not specify how addition is implemented. But to be realistic, the + operator on integer types smaller than or equal to the word size of your CPU get translated directly into an addition instruction for the CPU, and larger integer types get translated into multiple addition instructions with … Read more
This is because PHP uses the period character . for string concatenation, not the plus character +. Therefore to append to a string you want to use the .= operator: for ($i=1;$i<=100;$i++) { $selectBox .= ‘<option value=”‘ . $i . ‘”>’ . $i . ‘</option>’; } $selectBox .= ‘</select>’;
As a general rule: you pretty much never need the ternary operator in Ruby. The reason why you need it in C, is because in C if is a statement, so if you want to return a value you have to use the ternary operator, which is an expression. In Ruby, everything is an expression, … Read more
No, not all operators return something. Although they are probably not exactly what you are thinking about, note that the delete and delete[] C++ ‘keywords’ are actually operators; and they are defined as having the void return type – which means they evaluate to nothing (which is not ‘something’). From cppreference: void operator delete ( … Read more
String concatenation is done with + so Javascript will convert the first numeric 1 to a string and concatenate “1” and “1” making “11”. You cannot perform subtraction on strings, so Javascript converts the second “1” to a number and subtracts 1 from 1, resulting in zero.
Any compiler worth its salt will generate exactly the same machine-language sequence for both constructs for any built-in type (int, float, etc) as long as the statement really is as simple as x = x + a; and optimization is enabled. (Notably, GCC’s -O0, which is the default mode, performs anti-optimizations, such as inserting completely … Read more
According to §8.3.1 of The Design and Evolution of C++: The idea of providing an output operator rather than a named output function was suggested by Doug McIlroy by analogy with the I/O redirection operators in the UNIX shell (>, >>, |, etc.) […] Several operators were considered for input and output operations: the assignment … Read more
Simply use as a shortcut to “range”: you can construct a range and “~=” means “contains”. (other can add more theoretical details, but the sense is this). Read it as “contains” let n: Int = 100 // verify if n is in a range, say: 10 to 100 (included) if n>=10 && n<=100 { print(“inside!”) … Read more
It’s related to PEP 0401: BDFL Retirement Barry refers to Barry Warsaw, a well-known Python developer. The from __future__ import barry_as_FLUFL basically replaces the != operator with <>.