This is because of how the grammar of Java language is defined. Precedence of operators comes into play just when the same lexical sequence could be parsed in two different ways but this is not the case. Why? Because the allocation is defined in: Primary: … new Creator while method call is defined in: Selector: … Read more
RHS first and then LHS. And at any side, the evaluation order is left to right. a[-1] += a.pop() is same as, a[-1] = a[-1] + a.pop() a = [1,2,3] a[-1] = a[-1] + a.pop() # a = [1, 6] See how the behavior changes when we change the order of the operations at RHS, … Read more
This is explained in the Perl documentation. Because of Perl operator precedence the statement is being parsed as ($condition ? $a= 2 : $a ) = 3 ; Because the ?: operator produces an assignable result, 3 is assigned to the result of the condition. When $condition is true this means ($a=2)=3 giving $a=3 When … Read more
An AwaitExpression is a UnaryExpression and has the same precedence as delete, void, typeof, +, -, ~, and !, binding stronger than any binary operator. This is unlike yield which has a precedence lower than anything else except the comma operator. This design decision was made because both yield a+b and await a + await … Read more
After the first a++ a becomes 4. So you have 3 * 4 = 12. (a becomes 5 after the 2nd a++, but that is discarded, because the assignment a = overrides it)
MySQL does “left to right” evaluation and does “see” the new values. (Tested on 5.0.45-community-nt-log MySQL Community Edition) Furthermore, from the MySQL manual: “Single-table UPDATE assignments are generally evaluated from left to right. For multiple-table updates, there is no guarantee that assignments are carried out in any particular order.” Now, “generally” is quite vague and … Read more
Expressions are evaluated left to right. Parentheses (and precedence) just express grouping, they don’t express ordering of evaluation. So 11 * (12 + 5) ++a ++a equals 187
You need to ask Brian Kernighan or Dennis Ritchie. From this forum: http://bytes.com/topic/c/answers/167377-operator-precedence The && and || operators were added later for their “short-circuiting” behavior. Dennis Ritchie admits in retrospect that the precedence of the bitwise operators should have been changed when the logical operators were added. But with several hundred kilobytes of C source … Read more
With C++ there are only a few operators that guarantee the evaluation order operator && evaluates left operand first and if the value is logically false then it avoids evaluating the right operand. Typical use is for example if (x > 0 && k/x < limit) … that avoids division by zero problems. operator || … Read more
Well, for one thing it’s not clear whether you expect this to be insertion-order or key-order. For example, what would you expect the result to be if you wrote: var test = new Dictionary<int, string>(); test.Add(3, “three”); test.Add(2, “two”); test.Add(1, “one”); test.Add(0, “zero”); Console.WriteLine(test.ElementAt(0).Value); Would you expect “three” or “zero”? As it happens, I think … Read more