How can a query multiply 2 cell for each row MySQL?
Use this: SELECT Pieces, Price, Pieces * Price as ‘Total’ FROM myTable
Use this: SELECT Pieces, Price, Pieces * Price as ‘Total’ FROM myTable
What’s wrong with result = dataframe.mul(series, axis=0) ? https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.DataFrame.mul.html#pandas.DataFrame.mul
CPU’s ALU (Arithmetic-Logic Unit) executes algorithms, though they are implemented in hardware. Classic multiplications algorithms includes Wallace tree and Dadda tree. More information is available here. More sophisticated techniques are available in newer processors. Generally, processors strive to parallelize bit-pairs operations in order the minimize the clock cycles required. Multiplication algorithms can be parallelized quite … Read more
In NumPy it is quite simple import numpy as np P=2.45 S=[22, 33, 45.6, 21.6, 51.8] SP = P*np.array(S) I recommend taking a look at the NumPy tutorial for an explanation of the full capabilities of NumPy’s arrays: https://scipy.github.io/old-wiki/pages/Tentative_NumPy_Tutorial
Multiplication of two n-bit numbers can in fact be done in O(log n) circuit depth, just like addition. Addition in O(log n) is done by splitting the number in half and (recursively) adding the two parts in parallel, where the upper half is solved for both the “0-carry” and “1-carry” case. Once the lower half … Read more
Try a list comprehension: l = [x * 2 for x in l] This goes through l, multiplying each element by two. Of course, there’s more than one way to do it. If you’re into lambda functions and map, you can even do l = map(lambda x: x * 2, l) to apply the function … Read more
I think you’re looking for sweep(). # Create example data and vector mat <- matrix(rep(1:3,each=5),nrow=3,ncol=5,byrow=TRUE) [,1] [,2] [,3] [,4] [,5] [1,] 1 1 1 1 1 [2,] 2 2 2 2 2 [3,] 3 3 3 3 3 vec <- 1:5 # Use sweep to apply the vector with the multiply (`*`) function # across … Read more
1. Detecting the overflow: x = a * b; if (a != 0 && x / a != b) { // overflow handling } Edit: Fixed division by 0 (thanks Mark!) 2. Computing the carry is quite involved. One approach is to split both operands into half-words, then apply long multiplication to the half-words: uint64_t … Read more
To multiply in terms of adding and shifting you want to decompose one of the numbers by powers of two, like so: 21 * 5 = 10101_2 * 101_2 (Initial step) = 10101_2 * (1 * 2^2 + 0 * 2^1 + 1 * 2^0) = 10101_2 * 2^2 + 10101_2 * 2^0 = 10101_2 … Read more
Use a list comprehension mixed with zip():. [a*b for a,b in zip(lista,listb)]