Try this: function removeElementWithValue($array, $key, $value){ foreach($array as $subKey => $subArray){ if($subArray[$key] == $value){ unset($array[$subKey]); } } return $array; } Then you would call it like this: $array = removeElementWithValue($array, “year”, 2011);
x has a shape of (2, 3) (two rows and three columns): 1 1 1 1 1 1 By doing tf.reduce_sum(x, 0) the tensor is reduced along the first dimension (rows), so the result is [1, 1, 1] + [1, 1, 1] = [2, 2, 2]. By doing tf.reduce_sum(x, 1) the tensor is reduced along … Read more
Regardless what others are offering here, you are looking for a function called array_uniqueDocs. The important thing here is to set the second parameter to SORT_REGULAR and then the job is easy: array_unique($result, SORT_REGULAR); The meaning of the SORT_REGULAR flag is: compare items normally (don’t change types) And that is what you want. You want … Read more
Something like this? function listToMatrix(list, elementsPerSubArray) { var matrix = [], i, k; for (i = 0, k = -1; i < list.length; i++) { if (i % elementsPerSubArray === 0) { k++; matrix[k] = []; } matrix[k].push(list[i]); } return matrix; } Usage: var matrix = listToMatrix([1, 2, 3, 4, 4, 5, 6, 7, 8, … Read more
In php 5.5+ you can just used array_column and array_sum like so: $value = array_sum(array_column($arr,’f_count’));
Java doesn’t have multi-dimensional arrays. It has arrays of arrays. So for instance, int[][] …is an array of int[] (and of course int[] is an array of int). Consequently, Java is neither column-major nor row-major order (but see note below about how to read a[2][3]), because while a given array’s entries are stored in a … Read more
You can use a list of tuples, but the convention is different from what you want. numpy expects a list of row indices, followed by a list of column values. You, apparently, want to specify a list of (x,y) pairs. http://docs.scipy.org/doc/numpy/reference/arrays.indexing.html#integer-array-indexing The relevant section in the documentation is ‘integer array indexing’. Here’s an example, seeking … Read more
This code will not work in either C or C++. An array of type int[4][4] is not convertible to a pointer of type int ** (which is what int *arr[] stands for in parameter declaration). If you managed to compile it in C, it is simply because you probably ignored a C compiler warning of … Read more
In addition to the other answers, you can also use slicing with numpy.newaxis: >>> from numpy import zeros, newaxis >>> a = zeros((6, 8)) >>> a.shape (6, 8) >>> b = a[:, :, newaxis] >>> b.shape (6, 8, 1) Or even this (which will work with an arbitrary number of dimensions): >>> b = a[…, … Read more
As far as I can tell, there is no prebuilt solution for this, so you can just roll your own: function array_to_object($array) { $obj = new stdClass(); foreach ($array as $k => $v) { if (strlen($k)) { if (is_array($v)) { $obj->{$k} = array_to_object($v); //RECURSION } else { $obj->{$k} = $v; } } } return $obj; … Read more