def clamp(n, minn, maxn): return max(min(maxn, n), minn) or functionally equivalent: clamp = lambda n, minn, maxn: max(min(maxn, n), minn) now, you use: n = clamp(n, 7, 42) or make it perfectly clear: n = minn if n < minn else maxn if n > maxn else n even clearer: def clamp(n, minn, maxn): if … Read more
min_element and max_element return iterators, not values. So you need *min_element… and *max_element….
In [2]: min(data, key = lambda t: t[1]) Out[2]: (5, 0.01) or: In [3]: import operator In [4]: min(data, key=operator.itemgetter(1)) Out[4]: (5, 0.01)
fmin and fmax are specifically for use with floating point numbers (hence the “f”). If you use it for ints, you may suffer performance or precision losses due to conversion, function call overhead, etc. depending on your compiler/platform. std::min and std::max are template functions (defined in header <algorithm>) which work on any type with a … Read more
How about something like: SELECT mt.* FROM MyTable mt INNER JOIN ( SELECT id, MIN(record_date) AS MinDate FROM MyTable GROUP BY id ) t ON mt.id = t.id AND mt.record_date = t.MinDate This gets the minimum date per ID, and then gets the values based on those values. The only time you would have duplicates … Read more
What you want is this: IEnumerable<double> results = … your query … double result = results.MinOrDefault(); Well, MinOrDefault() does not exist. But if we were to implement it ourselves it would look something like this: public static class EnumerableExtensions { public static T MinOrDefault<T>(this IEnumerable<T> sequence) { if (sequence.Any()) { return sequence.Min(); } else { … Read more
Using CROSS APPLY: SELECT ID, Col1, Col2, Col3, MinValue FROM YourTable CROSS APPLY (SELECT MIN(d) AS MinValue FROM (VALUES (Col1), (Col2), (Col3)) AS a(d)) A SQL Fiddle
The tersest expressive code to find the minimum value is probably rest parameters: const arr = [14, 58, 20, 77, 66, 82, 42, 67, 42, 4] const min = Math.min(…arr) console.log(min) Rest parameters are essentially a convenient shorthand for Function.prototype.apply when you don’t need to change the function’s context: var arr = [14, 58, 20, … Read more
lst = [{‘price’: 99, ‘barcode’: ‘2342355’}, {‘price’: 88, ‘barcode’: ‘2345566’}] maxPricedItem = max(lst, key=lambda x:x[‘price’]) minPricedItem = min(lst, key=lambda x:x[‘price’]) This tells you not just what the max price is but also which item is most expensive.
Code is tested with IE,FF,Chrome and works properly: var dates=[]; dates.push(new Date(“2011/06/25”)) dates.push(new Date(“2011/06/26”)) dates.push(new Date(“2011/06/27”)) dates.push(new Date(“2011/06/28”)) var maxDate=new Date(Math.max.apply(null,dates)); var minDate=new Date(Math.min.apply(null,dates));