Assuming df has a unique index, this gives the row with the maximum value: In [34]: df.loc[df[‘Value’].idxmax()] Out[34]: Country US Place Kansas Value 894 Name: 7 Note that idxmax returns index labels. So if the DataFrame has duplicates in the index, the label may not uniquely identify the row, so df.loc may return more than … Read more
This is probably the best way, since it’s reliable and works on old browsers: function indexOfMax(arr) { if (arr.length === 0) { return -1; } var max = arr[0]; var maxIndex = 0; for (var i = 1; i < arr.length; i++) { if (arr[i] > max) { maxIndex = i; max = arr[i]; } … Read more
Using C++11/C++0x compile flags, you can auto it = max_element(std::begin(cloud), std::end(cloud)); // C++11 Otherwise, write your own: template <typename T, size_t N> const T* mybegin(const T (&a)[N]) { return a; } template <typename T, size_t N> const T* myend (const T (&a)[N]) { return a+N; } See it live at http://ideone.com/aDkhW: #include <iostream> #include <algorithm> … Read more
You can use idxmax with axis=1 to find the column with the greatest value on each row: >>> df.idxmax(axis=1) 0 Communications 1 Business 2 Communications 3 Communications 4 Business dtype: object To create the new column ‘Max’, use df[‘Max’] = df.idxmax(axis=1). To find the row index at which the maximum value occurs in each column, … Read more
np.max is just an alias for np.amax. This function only works on a single input array and finds the value of maximum element in that entire array (returning a scalar). Alternatively, it takes an axis argument and will find the maximum value along an axis of the input array (returning a new array). >>> a … Read more
a.index(max(a)) will tell you the index of the first instance of the largest valued element of list a.
Here is the solution I finally came up with when using a div as a container for a dynamic background. Remove the z-index for non-background uses. Remove left or right for a full height column. Remove top or bottom for a full width row. EDIT 1: CSS below has been edited because it did not … Read more
Resig to the rescue: Array.max = function( array ){ return Math.max.apply( Math, array ); }; Warning: since the maximum number of arguments is as low as 65535 on some VMs, use a for loop if you’re not certain the array is that small.
For float have a look at sys.float_info: >>> import sys >>> sys.float_info sys.floatinfo(max=1.7976931348623157e+308, max_exp=1024, max_10_exp=308, min=2.2 250738585072014e-308, min_exp=-1021, min_10_exp=-307, dig=15, mant_dig=53, epsil on=2.2204460492503131e-16, radix=2, rounds=1) Specifically, sys.float_info.max: >>> sys.float_info.max 1.7976931348623157e+308 If that’s not big enough, there’s always positive infinity: >>> infinity = float(“inf”) >>> infinity inf >>> infinity / 10000 inf The long type has … Read more
Let’s say you want to scale a range [min,max] to [a,b]. You’re looking for a (continuous) function that satisfies f(min) = a f(max) = b In your case, a would be 1 and b would be 30, but let’s start with something simpler and try to map [min,max] into the range [0,1]. Putting min into … Read more