How to convert a hexadecimal string to long in java?

Long.decode(str) accepts a variety of formats: Accepts decimal, hexadecimal, and octal numbers given by the following grammar: DecodableString: Signopt DecimalNumeral Signopt 0x HexDigits Signopt 0X HexDigits Signopt # HexDigits Signopt 0 OctalDigits Sign: – But in your case that won’t help, your String is beyond the scope of what long can hold. You need a … Read more

“OverflowError: Python int too large to convert to C long” on windows but not mac

You’ll get that error once your numbers are greater than sys.maxsize: >>> p = [sys.maxsize] >>> preds[0] = p >>> p = [sys.maxsize+1] >>> preds[0] = p Traceback (most recent call last): File “<stdin>”, line 1, in <module> OverflowError: Python int too large to convert to C long You can confirm this by checking: >>> … Read more

How to printf long long

%lld is the standard C99 way, but that doesn’t work on the compiler that I’m using (mingw32-gcc v4.6.0). The way to do it on this compiler is: %I64d So try this: if(e%n==0)printf(“%15I64d -> %1.16I64d\n”,e, 4*pi); and scanf(“%I64d”, &n); The only way I know of for doing this in a completely portable way is to use … Read more

A long bigger than Long.MAX_VALUE

That method can’t return true. That’s the point of Long.MAX_VALUE. It would be really confusing if its name were… false. Then it should be just called Long.SOME_FAIRLY_LARGE_VALUE and have literally zero reasonable uses. Just use Android’s isUserAGoat, or you may roll your own function that always returns false. Note that a long in memory takes … Read more

Long vs BigInteger

BigInteger is capable of holding far bigger numbers than Long. BigInteger seems capable of holding (2 ^ 32) ^ Integer.MAX_VALUE, though that depends on the implementation (and, even if truly unbounded in the implementation, there will eventually be a physical resource limit) See explanation here. The range of Long is [-9,223,372,036,854,775,808, +9,223,372,036,854,775,807]. Long will perform … Read more