endl appends ‘\n’ to the stream and calls flush() on the stream. So cout << x << endl; is equivalent to cout << x << ‘\n’; cout.flush(); A stream may use an internal buffer which gets actually streamed when the stream is flushed. In case of cout you may not notice the difference since it’s … Read more
The proper way to create a new stream in C++ is to derive from std::streambuf and to override the underflow() operation for reading and the overflow() and sync() operations for writing. For your purpose you’d create a filtering stream buffer which takes another stream buffer (and possibly a stream from which the stream buffer can … Read more
Click Project → Properties. Expand C/C++ General. Click Preprocessor Include Paths, Macros, etc. Click the Providers tab. Check CDT GCC Built-in Compiler Settings. Check Use global provider shared between projects. Click Apply and Close.
To read and write binary data to streams, including stringstreams, use the read() and write() member functions. So unsigned char a(1), b(2), c(3), d(4); std::stringstream s; s.write(reinterpret_cast<const char*>(&a), sizeof(unsigned char)); s.write(reinterpret_cast<const char*>(&b), sizeof(unsigned char)); s.write(reinterpret_cast<const char*>(&c), sizeof(unsigned char)); s.write(reinterpret_cast<const char*>(&d), sizeof(unsigned char)); s.read(reinterpret_cast<char*>(&v), sizeof(unsigned int)); std::cout << std::hex << v << “\n”; This gives 0x4030201 … Read more
Take a look at Apache Commons implementation of Tailer class. It does seem to handle log rotation as well.
char a = 0xab; cout << +a; // promotes a to a type printable as a number, regardless of type. This works as long as the type provides a unary + operator with ordinary semantics. If you are defining a class that represents a number, to provide a unary + operator with canonical semantics, create … Read more
This works for me in GCC: #include <iostream> #include <iomanip> using namespace std; int main() { cout << “0x” << setfill(‘0′) << setw(2) << right << hex << 10 << endl; } If you are getting sick and tired of iostream’s formatting quirkiness, give Boost.Format a try. It allows good-old-fashioned, printf-style format specifiers, yet it … Read more
To represent the character you can use Universal Character Names (UCNs). The character ‘ф’ has the Unicode value U+0444 and so in C++ you could write it ‘\u0444’ or ‘\U00000444’. Also if the source code encoding supports this character then you can just write it literally in your source code. // both of these assume … Read more
The question was on ostream to string, not ostringstream to string. For those interested in having the actual question answered (specific to ostream), try this: void someFunc(std::ostream out) { std::stringstream ss; ss << out.rdbuf(); std::string myString = ss.str(); }
I have verified a solution here using Visual Studio 2010. Via this MSDN article and MSDN blog post. The trick is an obscure call to _setmode(…, _O_U16TEXT). Solution: #include <iostream> #include <io.h> #include <fcntl.h> int wmain(int argc, wchar_t* argv[]) { _setmode(_fileno(stdout), _O_U16TEXT); std::wcout << L”Testing unicode — English — Ελληνικά — Español.” << std::endl; } … Read more