How to generate a random number in Elixir?
You can call Erlang’s rand module from Elixir code seamlessly. random_number = :rand.uniform(n) Will give a random number from 1 <= x <= n
You can call Erlang’s rand module from Elixir code seamlessly. random_number = :rand.uniform(n) Will give a random number from 1 <= x <= n
uint_least8_t is the smallest type that has at least 8 bits. uint_fast8_t is the fastest type that has at least 8 bits. You can see the differences by imagining exotic architectures. Imagine a 20-bit architecture. Its unsigned int has 20 bits (one register), and its unsigned char has 10 bits. So sizeof(int) == 2, but … Read more
The minimum ranges you can rely on are: short int and int: -32,767 to 32,767 unsigned short int and unsigned int: 0 to 65,535 long int: -2,147,483,647 to 2,147,483,647 unsigned long int: 0 to 4,294,967,295 This means that no, long int cannot be relied upon to store any 10-digit number. However, a larger type, long … Read more
String.format(“%02X”, value); If you use X instead of x as suggested by aristar, then you don’t need to use .toUpperCase().
As already written elsewhere: For Java 1.5 and later you don’t need to do (almost) anything, it’s done by the compiler. For Java 1.4 and before, use Integer.intValue() to convert from Integer to int. BUT as you wrote, an Integer can be null, so it’s wise to check that before trying to convert to int … Read more
I’ll add to the other answers also that using uint as type of a public field, property, method, parameter, and so on, is a violation of the Common Language Specification rules and to be avoided when possible.
JavaScript represents numbers using IEEE-754 double-precision (64 bit) format. As I understand it this gives you 53 bits precision, or fifteen to sixteen decimal digits. Your number has more digits than JavaScript can cope with, so you end up with an approximation. This isn’t really “mishandling” as such, but obviously it isn’t very helpful if … Read more
The read method returns a sequence of bytes as a string. To convert from a string byte-sequence to binary data, use the built-in struct module: http://docs.python.org/library/struct.html. import struct print(struct.unpack(‘i’, fin.read(4))) Note that unpack always returns a tuple, so struct.unpack(‘i’, fin.read(4))[0] gives the integer value that you are after. You should probably use the format string … Read more
How about this? “1,112”.delete(‘,’).to_i
a) Can you explain to me the difference between int64_t and long (long int)? In my understanding, both are 64 bit integers. Is there any reason to choose one over the other? The former is a signed integer type with exactly 64 bits. The latter is a signed integer type with at least 32 bits. … Read more