http-post

How to POST URL in data of a curl request

by

Perhaps you don’t have to include the single quotes: curl –request POST ‘http://localhost/Service’ –data “path=/xyz/pqr/test/&fileName=1.doc” Update: Reading curl’s manual, you could actually separate both fields with two –data: curl –request POST ‘http://localhost/Service’ –data “path=/xyz/pqr/test/” –data “fileName=1.doc” You could also try –data-binary: curl –request POST ‘http://localhost/Service’ –data-binary “path=/xyz/pqr/test/” –data-binary “fileName=1.doc” And –data-urlencode: curl –request POST ‘http://localhost/Service’ … Read more

Apache 301 Redirect and preserving post data

by

Using a 307 should be exactly what you want 307 Temporary Redirect (since HTTP/1.1) In this case, the request should be repeated with another URI; however, future requests should still use the original URI.[2] In contrast to how 302 was historically implemented, the request method is not allowed to be changed when reissuing the original … Read more

Post FromBody Always Null

by

You get always null because you need to encapsulate all your post variables inside only one object. Like this: public class MyPostModel { public List<string> userSocs {get; set;} public int collegeId {get; set;} } and then public async Task<IActionResult> GetStudentResults([FromBody] MyPostModel postModel)

Multiline curl command

by

For Linux and MacOS: Use the \ escape character: curl “http://WEBSITE” -H “Host: WEBSITE” \ -H “Accept: text/html,application/xhtml+xml \ ,application/xml;q=0.9,*/*;q=0.8” For Windows: Use the ^ escape character: curl “http://WEBSITE” -H “Host: WEBSITE” ^ -H “Accept: text/html,application/xhtml+xml ^ ,application/xml;q=0.9,*/*;q=0.8”

Uploading Images to Server android

by

Intent photoPickerIntent = new Intent(Intent.ACTION_PICK); photoPickerIntent.setType(“image/*”); startActivityForResult(photoPickerIntent, 1); ABOVE CODE TO SELECT IMAGE FROM GALLERY @Override public void onActivityResult(int requestCode, int resultCode, Intent data) { super.onActivityResult(requestCode, resultCode, data); if (requestCode == 1) if (resultCode == Activity.RESULT_OK) { Uri selectedImage = data.getData(); String filePath = getPath(selectedImage); String file_extn = filePath.substring(filePath.lastIndexOf(“.”) + 1); image_name_tv.setText(filePath); try { if … Read more

Send JSON POST request with PHP

by

You can use CURL for this purpose see the example code: $url = “your url”; $content = json_encode(“your data to be sent”); $curl = curl_init($url); curl_setopt($curl, CURLOPT_HEADER, false); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_HTTPHEADER, array(“Content-type: application/json”)); curl_setopt($curl, CURLOPT_POST, true); curl_setopt($curl, CURLOPT_POSTFIELDS, $content); $json_response = curl_exec($curl); $status = curl_getinfo($curl, CURLINFO_HTTP_CODE); if ( $status != 201 ) { … Read more

How can I pass POST parameters in a URL?

by

You could use a form styled as a link. No JavaScript is required: <form action=”/do/stuff.php” method=”post”> <input type=”hidden” name=”user_id” value=”123″ /> <button>Go to user 123</button> </form> CSS: button { border: 0; padding: 0; display: inline; background: none; text-decoration: underline; color: blue; } button:hover { cursor: pointer; } See: http://jsfiddle.net/SkQRN/

View not updating after post

by

it should be the ModelState problem. if you use Htmlhelper to Display id value. Default HtmlHelper display ModelState value not Model. Try display model value in view <td> @Model.id </td> or Clean ModelState Value in controller ModelState.Clear(); or reset id value after SaveChange. theCar.Save(); ModelState[“id”].Value = theCar.id return View(theCar); Reset the value of textarea after … Read more