Depending on how many colors you want to end up with, the solution is just to keep incrementing the green value by a certain amount, and then when green is maxed (FF), decrement the red value repeatedly by the same amount. Pseudo-code: int red = 255; //i.e. FF int green = 0; int stepSize = … Read more
R: 128 G: 128 B: 128 or #808080
Colors are always returned as rgb (except IE6 which already returns in hex), then we cannot return in another format natively. Like you said, you can write a function to convert hex to rgb. Here is a topic with several examples of how to write this function: How to get hex color value rather than … Read more
If you’re working in Node or using Browserify, you can use var base64String = Buffer.from(hexString, ‘hex’).toString(‘base64’) or var hexString = Buffer.from(base64String, ‘base64’).toString(‘hex’)
The usual way is to use String#getBytes() to get the underlying bytes and then present those bytes in some other form (hex, binary whatever). Note that getBytes() uses the default charset, so if you want the string converted to some specific character encoding, you should use getBytes(String encoding) instead, but many times (esp when dealing … Read more
In Python 3: >>> import struct >>> struct.unpack(‘!f’, bytes.fromhex(‘41973333’))[0] 18.899999618530273 >>> struct.unpack(‘!f’, bytes.fromhex(‘41995C29’))[0] 19.170000076293945 >>> struct.unpack(‘!f’, bytes.fromhex(‘470FC614’))[0] 36806.078125 In Python 2: >>> import struct >>> struct.unpack(‘!f’, ‘41973333’.decode(‘hex’))[0] 18.899999618530273 >>> struct.unpack(‘!f’, ‘41995C29’.decode(‘hex’))[0] 19.170000076293945 >>> struct.unpack(‘!f’, ‘470FC614’.decode(‘hex’))[0] 36806.078125
Ways without dynamic SQL There is no cast from hex numbers in text representation to a numeric type, but we can use bit(n) as waypoint. There are undocumented casts from bit strings (bit(n)) to integer types (int2, int4, int8) – the internal representation is binary compatible. Quoting Tom Lane: This is relying on some undocumented … Read more
Will this help? Integer.parseInt(“00ff00”, 16) 16 means that you should interpret the string as 16-based (hexadecimal). By using 2 you can parse binary number, 8 stands for octal. 10 is default and parses decimal numbers. In your case Integer.parseInt(primary.getFullHex(), 16) won’t work due to 0x prefix prepended by getFullHex() – get rid of and you’ll … Read more
Easiest way is to use String.Format and use the hexadecimal format for the argument. var random = new Random(); var color = String.Format(“#{0:X6}”, random.Next(0x1000000)); // = “#A197B9”
Strings in Java are always encoded in UTF-16, so it uses a Unicode escape: \u0048. Octal characters are supported as well: \110