You can also do it with recursion: def reverse(text): if len(text) <= 1: return text return reverse(text[1:]) + text[0] And a simple example for the string hello: reverse(hello) = reverse(ello) + h # The recursive step = reverse(llo) + e + h = reverse(lo) + l + e + h = reverse(o) + l + … Read more
It’s an infinite loop, equivalent to while(true). When no termination condition is provided, the condition defaults to false (i.e., the loop will not terminate).
The commandline interpreter does indeed have a FOR construct that you can use from the command prompt or from within a batch file. For your purpose, you probably want something like: FOR %i IN (*.ext) DO my-function %i Which will result in the name of each file with extension *.ext in the current directory being … Read more
Either use return, as the closure basically is a method that is called with each element as parameter like def myObj = [“Hello”, “World!”, “How”, “Are”, “You”] myList.each{ myObj-> if(myObj==null){ return } println(“My Object is ” + myObj) } Or switch your pattern to def myObj = [“Hello”, “World!”, “How”, “Are”, “You”] myList.each{ myObj-> if(myObj!=null){ … Read more
I think you should use slice to achieve your goal {% for account in object_list|slice:”:1″ %}
The accepted answer is not right because any decent engine should be able to hoist the property load out of the loop with so simple loop bodies. See this jsperf – at least in V8 it is interesting to see how actually storing it in a variable changes the register allocation – in the code … Read more
The code should be as follows (note the shebang says bash, not sh): #!/bin/bash echo “Bash version ${BASH_VERSION}…” for i in {1..10} do echo “Welcome $i times” done You can use {0..10..1} if you want to start from 0. Source: http://www.cyberciti.biz/faq/bash-for-loop/.
You’re modifying the list while you iterate over it. That means that the first time through the loop, i == 1, so 1 is removed from the list. Then the for loop goes to the second item in the list, which is not 2, but 3! Then that’s removed from the list, and then the … Read more
Use the old for loop as: for (auto it = values.begin(); it != values.end(); ++it ) { auto & value = *it; //… } With this, you’ve value as well as iterator it. Use whatever you want to use. EDIT: Although I wouldn’t recommended this, but if you want to use range-based for loop (yeah, … Read more
The following for-of loop works: for (const e of a) The ES6 specification describes this as: ForDeclaration : LetOrConst ForBinding http://www.ecma-international.org/ecma-262/6.0/index.html#sec-for-in-and-for-of-statements-static-semantics-boundnames The imperative for loop will not work: for (const i = 0; i < a.length; i += 1) This is because the declaration is only evaluated once before the loop body is executed. http://www.ecma-international.org/ecma-262/6.0/index.html#sec-for-statement-runtime-semantics-labelledevaluation