You should always use open(). As the documentation states: When opening a file, it’s preferable to use open() instead of invoking this constructor directly. file is more suited to type testing (for example, writing “isinstance(f, file)”). Also, file() has been removed since Python 3.0.
You need to stringify the object. fs.writeFileSync(‘../data/phraseFreqs.json’, JSON.stringify(output));
The easiest thing to do is just P/Invoke the built-in function in Windows, and use it as the comparison function in your IComparer: [DllImport(“shlwapi.dll”, CharSet = CharSet.Unicode)] private static extern int StrCmpLogicalW(string psz1, string psz2); Michael Kaplan has some examples of how this function works here, and the changes that were made for Vista to … Read more
You are reading all rows into a list, then processing that list. Don’t do that. Process your rows as you produce them. If you need to filter the data first, use a generator function: import csv def getstuff(filename, criterion): with open(filename, “rb”) as csvfile: datareader = csv.reader(csvfile) yield next(datareader) # yield the header row count … Read more
You can use Java jar tool. List the content of jar file in a txt file and you can see all the classes in the jar. jar tvf jarfile.jar -t list table of contents for archive -v generate verbose output on standard output -f specify archive file name
Here is a sample: <?php // Snippet from PHP Share: http://www.phpshare.org function formatSizeUnits($bytes) { if ($bytes >= 1073741824) { $bytes = number_format($bytes / 1073741824, 2) . ‘ GB’; } elseif ($bytes >= 1048576) { $bytes = number_format($bytes / 1048576, 2) . ‘ MB’; } elseif ($bytes >= 1024) { $bytes = number_format($bytes / 1024, 2) … Read more
This concerns Java versions 7 and earlier. To quote a good answer to the same question: If you want it back as a string later, you can call getPath(). Indeed, if you really wanted to mimic Path.Combine, you could just write something like: public static String combine (String path1, String path2) { File file1 = … Read more
CodeSource src = MyClass.class.getProtectionDomain().getCodeSource(); if (src != null) { URL jar = src.getLocation(); ZipInputStream zip = new ZipInputStream(jar.openStream()); while(true) { ZipEntry e = zip.getNextEntry(); if (e == null) break; String name = e.getName(); if (name.startsWith(“path/to/your/dir/”)) { /* Do something with this entry. */ … } } } else { /* Fail… */ } Note that … Read more
Way 1: only works for dataURL, not for other types of url. function dataURLtoFile(dataurl, filename) { var arr = dataurl.split(‘,’), mime = arr[0].match(/:(.*?);/)[1], bstr = atob(arr[1]), n = bstr.length, u8arr = new Uint8Array(n); while(n–){ u8arr[n] = bstr.charCodeAt(n); } return new File([u8arr], filename, {type:mime}); } //Usage example: var file = dataURLtoFile(‘data:text/plain;base64,aGVsbG8gd29ybGQ=’,’hello.txt’); console.log(file); Way 2: works for … Read more
If you want to do this the C++ way, do it like this: #include <fstream> #include <iterator> #include <algorithm> int main() { std::ifstream input( “C:\\Final.gif”, std::ios::binary ); std::ofstream output( “C:\\myfile.gif”, std::ios::binary ); std::copy( std::istreambuf_iterator<char>(input), std::istreambuf_iterator<char>( ), std::ostreambuf_iterator<char>(output)); } If you need that data in a buffer to modify it or something, do this: #include <fstream> … Read more