Python supports arbitrary precision integers, meaning you’re able to represent larger numbers than a normal 32 or 64 bit integer type. The L tells you when a literal is of this type and not a regular integer. Note, that L only shows up in the interpreter output, it’s just signifying the type. If you print … Read more
There is no operator, but there is a method. Math.pow(2, 3) // 8.0 Math.pow(3, 2) // 9.0 FYI, a common mistake is to assume 2 ^ 3 is 2 to the 3rd power. It is not. The caret is a valid operator in Java (and similar languages), but it is binary xor.
Operator ^ is a bitwise operator, which does bitwise exclusive or. The power operator is **, like 8**3 which equals to 512.
sort with ‘-g’ option should do the trick for you. -g option indicates ‘use generic numerical value’ for sorting
Another answer because this is very different from my previous answer, and this is blazing fast. Relative error is 3e-8. Want more accuracy? Add a couple more Chebychev terms. It’s best to keep the order odd as this makes for a small discontinuity between 2^n-epsilon and 2^n+epsilon. #include <stdlib.h> #include <math.h> // Returns x^(5/12) for … Read more
It is valid according to the format available at json.org as numbers can optionally have a base 10 exponent denoted by an E, uppercase or lowercase, an optional plus or minus, and one or more digits.
There are actually three exponentiation operators: (^), (^^) and (**). ^ is non-negative integral exponentiation, ^^ is integer exponentiation, and ** is floating-point exponentiation: (^) :: (Num a, Integral b) => a -> b -> a (^^) :: (Fractional a, Integral b) => a -> b -> a (**) :: Floating a => a -> … Read more
It is a floating point number, you have to tell it that: decimal d = Decimal.Parse(“1.2345E-02”, System.Globalization.NumberStyles.Float);
The C# language doesn’t have a power operator. However, the .NET Framework offers the Math.Pow method: Returns a specified number raised to the specified power. So your example would look like this: float Result, Number1, Number2; Number1 = 2; Number2 = 2; Result = Math.Pow(Number1, Number2);