Answer for python enumerate: In R, a list is ordered (see this answer). Thus, all you need is to index either keys (using names()[i]) or values (using [[i]]). Using seq_along (alternatively can do for(i in 1:length(mylist)){…}): > mylist <- list(‘a’=10,’b’=20,’c’=30) > for (i in seq_along(mylist)){ + print(paste(i,names(mylist)[i],mylist[[i]])) + } [1] “1 a 10” [1] “2 … Read more
You can use enumerate inside a list-comprehension: indices = [i for i, s in enumerate(mylist) if ‘aa’ in s]
It’s lazy. It’s fairly easy to prove that’s the case: >>> def abc(): … letters = [‘a’,’b’,’c’] … for letter in letters: … print letter … yield letter … >>> numbered = enumerate(abc()) >>> for i, word in numbered: … print i, word … a 0 a b 1 b c 2 c
This will work for general reading a String from Text. If you would like to read longer text (large size of text), then use the method that other people here were mentioned such as buffered (reserve the size of the text in memory space). Say you read a Text File. NSString* filePath = @””//file path… … Read more
Yes, absolutely. Using Reflection: static IEnumerable<Type> GetTypesWithHelpAttribute(Assembly assembly) { foreach(Type type in assembly.GetTypes()) { if (type.GetCustomAttributes(typeof(HelpAttribute), true).Length > 0) { yield return type; } } }
The enumerate() function adds a counter to an iterable. So for each element in cursor, a tuple is produced with (counter, element); the for loop binds that to row_number and row, respectively. Demo: >>> elements = (‘foo’, ‘bar’, ‘baz’) >>> for elem in elements: … print elem … foo bar baz >>> for count, elem … Read more
This post is relevant here https://www.swift-studies.com/blog/2014/6/10/enumerating-enums-in-swift Essentially the proposed solution is enum ProductCategory : String { case Washers = “washers”, Dryers = “dryers”, Toasters = “toasters” static let allValues = [Washers, Dryers, Toasters] } for category in ProductCategory.allValues{ //Do something }