Use the overload of String.format which lets you specify the locale: return String.format(Locale.ROOT, “%.2f”, someDouble); If you’re only formatting a number – as you are here – then using NumberFormat would probably be more appropriate. But if you need the rest of the formatting capabilities of String.format, this should work fine.
I almost never do two queries. Simply return one more row than is needed, only display 10 on the page, and if there are more than are displayed, display a “Next” button. SELECT x, y, z FROM `table` WHERE `some_condition` LIMIT 0, 11 // Iterate through and display 10 rows. // if there were 11 … Read more
If you like, you could declare an infix operator to do it. // Put this at file level anywhere in your project infix operator ^^ { associativity left precedence 160 } func ^^ (radix: Int, power: Int) -> Int { return Int(pow(Double(radix), Double(power))) } // … // Then you can do this… let i = … Read more
In Java, a – b is never equal to 0 if a != b. This is because Java mandates IEEE 754 floating point operations which support denormalized numbers. From the spec: In particular, the Java programming language requires support of IEEE 754 denormalized floating-point numbers and gradual underflow, which make it easier to prove desirable … Read more
One of the way would be using NumberFormat. NumberFormat formatter = new DecimalFormat(“#0.00”); System.out.println(formatter.format(4.0)); Output: 4.00
What is the return type of the round() method in the snippet? If this is the Math.round() method, it returns a Long when the input param is Double. So, you will have to cast the return value: int a = (int) Math.round(doubleVar);
This is because you are using the integer division version of operator/, which takes 2 ints and returns an int. In order to use the double version, which returns a double, at least one of the ints must be explicitly casted to a double. c = a/(double)b;
It is not casting, it is creating a string from a value with a format. let a: Double = 1.5 let b: String = String(format: “%f”, a) print(“b: \(b)”) // b: 1.500000 With a different format: let c: String = String(format: “%.1f”, a) print(“c: \(c)”) // c: 1.5 You can also omit the format property … Read more
You can use scala.math.BigDecimal: BigDecimal(1.23456789).setScale(2, BigDecimal.RoundingMode.HALF_UP).toDouble There are a number of other rounding modes, which unfortunately aren’t very well documented at present (although their Java equivalents are).
Because nextDouble works like this: (source) public double nextDouble() { return (((long) next(26) << 27) + next(27)) / (double) (1L << 53); } next(x) makes x random bits. Now why does this matter? Because about half the numbers generated by the first part (before the division) are less than 1L << 52, and therefore their … Read more