How to make C++ cout not use scientific notation
Use std::fixed stream manipulator: cout<<fixed<<“Bas ana: “<<x<<“\tSon faiz: “<<t<<“\tSon ana: “<<x+t<<endl;
Use std::fixed stream manipulator: cout<<fixed<<“Bas ana: “<<x<<“\tSon faiz: “<<t<<“\tSon ana: “<<x+t<<endl;
I’d say the answer depends on the rounding mode when converting the double to float. float has 24 binary bits of precision, and double has 53. In binary, 0.1 is: 0.1₁₀ = 0.0001100110011001100110011001100110011001100110011…₂ ^ ^ ^ ^ 1 10 20 24 So if we round up at the 24th digit, we’ll get 0.1₁₀ ~ 0.000110011001100110011001101 … Read more
Java doubles are in IEEE-754 format, therefore they have a 52-bit fraction; between any two adjacent powers of two (inclusive of one and exclusive of the next one), there will therefore be 2 to the 52th power different doubles (i.e., 4503599627370496 of them). For example, that’s the number of distinct doubles between 0.5 included and … Read more
You can specify a format string after an expression with a colon (:): var aNumberAsString = $”{aDoubleValue:0.####}”;
Am I wrong in assuming it should be faster and more efficient? I’d hate to go through and change everything in a massive program to find out I wasted my time. Short answer Yes, you are wrong. In most cases, it makes little difference in terms of space used. It is not worth trying to … Read more
yourTextView.setText(String.format(“Value of a: %.2f”, a));
It’s not that you’re actually getting extra precision – it’s that the float didn’t accurately represent the number you were aiming for originally. The double is representing the original float accurately; toString is showing the “extra” data which was already present. For example (and these numbers aren’t right, I’m just making things up) suppose you … Read more
If you want that for display purposes, use java.text.DecimalFormat: new DecimalFormat(“#.##”).format(dblVar); If you need it for calculations, use java.lang.Math: Math.floor(value * 100) / 100;
Use a format string to round up to two decimal places and convert the double to a String: let currentRatio = Double (rxCurrentTextField.text!)! / Double (txCurrentTextField.text!)! railRatioLabelField.text! = String(format: “%.2f”, currentRatio) Example: let myDouble = 3.141 let doubleStr = String(format: “%.2f”, myDouble) // “3.14” If you want to round up your last decimal place, you … Read more
From this post: How to deal with floating point number precision in JavaScript? You have a few options: Use a special datatype for decimals, like decimal.js Format your result to some fixed number of significant digits, like this: (Math.floor(y/x) * x).toFixed(2) Convert all your numbers to integers