How about simply: # If you want ‘modified time’, oldest first files_sorted_by_time = Dir[‘*’].sort_by{ |f| File.mtime(f) } # If you want ‘directory change time’ (creation time for Windows) files_sorted_by_time = Dir[‘*’].sort_by{ |f| File.ctime(f) }
The DefaultServlet of Tomcat is by default configured to not show directory listings. You need to open Tomcat’s own /conf/web.xml file (look in Tomcat installation folder), search the <servlet> entry of the DefaultServlet and then change its listings initialization parameter from <init-param> <param-name>listings</param-name> <param-value>false</param-value> </init-param> to <init-param> <param-name>listings</param-name> <param-value>true</param-value> </init-param> Keep in mind that this … Read more
I hate having to install libraries (especially those that want me to use installer packages to install them). If you’re looking for a clean solution for a directory listing on an absolute path in Lua, look no further. Building on the answer that sylvanaar provided, I created a function that returns an array of all … Read more
Try this: FtpWebRequest ftpRequest = (FtpWebRequest)WebRequest.Create(uri); ftpRequest.Credentials =new NetworkCredential(“anonymous”,”janeDoe@contoso.com”); ftpRequest.Method = WebRequestMethods.Ftp.ListDirectory; FtpWebResponse response = (FtpWebResponse)ftpRequest.GetResponse(); StreamReader streamReader = new StreamReader(response.GetResponseStream()); List<string> directories = new List<string>(); string line = streamReader.ReadLine(); while (!string.IsNullOrEmpty(line)) { directories.Add(line); line = streamReader.ReadLine(); } streamReader.Close(); It gave me a list of directories… all listed in the directories string list… tell me … Read more
In windows, to list only directories: dir /ad /b /s to list all files (and no directories): dir /a-d /b /s redirect the output to a file: dir /a-d /b /s > filename.txt dir command parameters explained on wikipedia
I’ve found this more useful and easy to use: Dir.chdir(‘/destination_directory’) Dir.glob(‘*’).select {|f| File.directory? f} it gets all folders in the current directory, excluded . and … To recurse folders simply use ** in place of *. The Dir.glob line can also be passed to Dir.chdir as a block: Dir.chdir(‘/destination directory’) do Dir.glob(‘*’).select { |f| File.directory? … Read more
This code works for me: import groovy.io.FileType def list = [] def dir = new File(“path_to_parent_dir”) dir.eachFileRecurse (FileType.FILES) { file -> list << file } Afterwards the list variable contains all files (java.io.File) of the given directory and its subdirectories: list.each { println it.path }
You can use the builtin sorted function to sort the strings however you want. Based on what you describe, sorted(os.listdir(whatever_directory)) Alternatively, you can use the .sort method of a list: lst = os.listdir(whatever_directory) lst.sort() I think should do the trick. Note that the order that os.listdir gets the filenames is probably completely dependent on your … Read more
You can use: dir /s If you need the list without all the header/footer information try this: dir /s /b (For sure this will work for DOS 6 and later; might have worked prior to that, but I can’t recall.)
search_dir=/the/path/to/base/dir/ for entry in “$search_dir”/* do echo “$entry” done