Use the ToDictionary method directly. var result = // as Jon Skeet pointed out, OrderBy is useless here, I just leave it // show how to use OrderBy in a LINQ query myClassCollection.OrderBy(mc => mc.SomePropToSortOn) .ToDictionary(mc => mc.KeyProp.ToString(), mc => mc.ValueProp.ToString(), StringComparer.OrdinalIgnoreCase);
You can use defaultdict: >>> from collections import defaultdict >>> d = defaultdict(list) >>> a = [‘1’, ‘2’] >>> for i in a: … for j in range(int(i), int(i) + 2): … d[j].append(i) … >>> d defaultdict(<type ‘list’>, {1: [‘1’], 2: [‘1’, ‘2’], 3: [‘2’]}) >>> d.items() [(1, [‘1’]), (2, [‘1’, ‘2’]), (3, [‘2’])]
Try this: [dict(t) for t in {tuple(d.items()) for d in l}] The strategy is to convert the list of dictionaries to a list of tuples where the tuples contain the items of the dictionary. Since the tuples can be hashed, you can remove duplicates using set (using a set comprehension here, older python alternative would … Read more
What about /usr/share/dict/words on any Unix system? How many words are we talking about? Like OED-Unabridged?
import csv to_csv = [ {‘name’: ‘bob’, ‘age’: 25, ‘weight’: 200}, {‘name’: ‘jim’, ‘age’: 31, ‘weight’: 180}, ] keys = to_csv[0].keys() with open(‘people.csv’, ‘w’, newline=””) as output_file: dict_writer = csv.DictWriter(output_file, keys) dict_writer.writeheader() dict_writer.writerows(to_csv)
A KeyError generally means the key doesn’t exist. So, are you sure the path key exists? From the official python docs: exception KeyError Raised when a mapping (dictionary) key is not found in the set of existing keys. For example: >>> mydict = {‘a’:’1′,’b’:’2′} >>> mydict[‘a’] ‘1’ >>> mydict[‘c’] Traceback (most recent call last): File … Read more
Is this good for you? geopoint = {‘latitude’:41.123,’longitude’:71.091} print(‘{latitude} {longitude}’.format(**geopoint))
>>> d = { ‘a’: 1, ‘b’: 2, ‘c’: 3 } >>> list(d.items()) [(‘a’, 1), (‘c’, 3), (‘b’, 2)] For Python 3.6 and later, the order of the list is what you would expect. In Python 2, you don’t need list.
Python 2 and Python 3 i is the key, so you would just need to use it: for i in d: print i, d[i] Python 3 d.items() returns the iterator; to get a list, you need to pass the iterator to list() yourself. for k, v in d.items(): print(k, v) Python 2 You can get … Read more
Two terms for the same thing: “Map” is used by Java, C++ “Dictionary” is used by .Net, Python “Associative array” is used by PHP “Map” is the correct mathematical term, but it is avoided because it has a separate meaning in functional programming. Some languages use still other terms (“Object” in Javascript, “Hash” in Ruby, … Read more