You can use File.lastModified() to get the last modified time of a file/directory. Can be used like this: long diff = new Date().getTime() – file.lastModified(); if (diff > x * 24 * 60 * 60 * 1000) { file.delete(); } Which deletes files older than x (an int) days.
The following snippet worked for me (deletes all *.exe files from a Zip archive): zin = zipfile.ZipFile (‘archive.zip’, ‘r’) zout = zipfile.ZipFile (‘archve_new.zip’, ‘w’) for item in zin.infolist(): buffer = zin.read(item.filename) if (item.filename[-4:] != ‘.exe’): zout.writestr(item, buffer) zout.close() zin.close() If you read everything into memory, you can eliminate the need for a second file. However, … Read more
npocmaka’s answer works, but it generates the following error message: “The batch file cannot be found.” This isn’t a problem if the console window closes when the script terminates, as the message will flash by so fast, no one will see it. But it is very undesirable if the console remains open after the script … Read more
Did you tried something like this : IF EXIST [Filename] ( del [Filename] ) ELSE ( … )
The problem could also be due to any output streams that you have forgotten to close. In my case I was working with the file before the file being deleted. However at one place in the file operations, I had forgotten to close an output stream that I used to write to the file that … Read more
You can combine NIO 2 and the Stream API. Path rootPath = Paths.get(“/data/to-delete”); // before you copy and paste the snippet // – read the post till the end // – read the javadoc to understand what the code will do // // a) to follow softlinks (removes the linked file too) use // Files.walk(rootPath, … Read more
Do yourself a favour and do not do git checkout <hash> like the other answer suggests and go into more problems. IF you have deleted file from your working directory and not committed the changes yet, do: git checkout -f CAUTION: commit uncommitted files before executing this command, otherwise you’re going to lose them all … Read more
This works for me: find /path ! -newermt “YYYY-MM-DD HH:MM:SS” | xargs rm -rf
Why don’t you test this with this code: File fdelete = new File(uri.getPath()); if (fdelete.exists()) { if (fdelete.delete()) { System.out.println(“file Deleted :” + uri.getPath()); } else { System.out.println(“file not Deleted :” + uri.getPath()); } } I think part of the problem is you never try to delete the file, you just keep creating a variable … Read more
Maybe you’re just looking for a combination of file.remove and list.files? Maybe something like: do.call(file.remove, list(list.files(“C:/Temp”, full.names = TRUE))) And I guess you can filter the list of files down to those whose names match a certain pattern using grep or grepl, no?