What is the best way to compare 2 folder trees on windows? [closed]
If you can use a GUI tool, the best I tried is WinMerge – open source. If not, then diff is your friend.
If you can use a GUI tool, the best I tried is WinMerge – open source. If not, then diff is your friend.
It’s hard to say which one is “better”…. First – there’s the whole underlying “Java vs. .NET” argument – you can’t really compare the frameworks ignoring this. The whole history of web development in Java with “heavyweight” J2EE apps vs. “lightweight” Spring apps. That in Java there are a ton of web frameworks (MVC and … Read more
This script works! #/bin/bash if [[ ( “$#” < 1 ) || ( !( “$1” == 1 ) && !( “$1” == 0 ) ) ]] ; then echo this script requires a 1 or 0 as first parameter. else echo “first parameter is $1” xinput set-prop 12 “Device Enabled” $0 fi But this also … Read more
Your compare() method is not transitive. If A == B and B == C, then A must be equal to C. Now consider this case: For A, B, and C, suppose the containsKey() method return these results: childMap.containsKey(A.getID()) returns true childMap.containsKey(B.getID()) returns false childMap.containsKey(C.getID()) returns true Also, consider orders for A.getId() != B.getId(). So, A … Read more
Your reasoning is that Double.POSITIVE_INFINITY should not be equal to itself because it is “likely” to have been obtained as the result of a loss of accuracy. This line of reasoning applies to all of floating-point. Any finite value can be obtained as the result of an inaccurate operation. That did not push the IEEE … Read more
import difflib lines1 = ”’ dog cat bird buffalo gophers hound horse ”’.strip().splitlines() lines2 = ”’ cat dog bird buffalo gopher horse mouse ”’.strip().splitlines() # Changes: # swapped positions of cat and dog # changed gophers to gopher # removed hound # added mouse for line in difflib.unified_diff(lines1, lines2, fromfile=”file1″, tofile=”file2″, lineterm=”): print line Outputs … Read more
There are various different ways of doing this. Have a look at the Wikipedia “String similarity measures” page for links to other pages with algorithms. I don’t think any of those algorithms take sounds into consideration, however – so “staq overflow” would be as similar to “stack overflow” as “staw overflow” despite the first being … Read more
You could take a look at two answers on SO itself: this one is about image comparison itself, offering links to stuff in C++ (if I read correctly) while this one offers links to broader approaches, one being in C. I would suggest starting with the second link since there’s links on that discussion that’ll … Read more
If they’re from the exact same class: boolean result = object1.getClass().equals( object2.getClass()); Now if they are compatible classes (if one is of a descendent class to the other): HashMap<String,Object> hashMap = new HashMap<String,Object>(); LinkedHashMap<String,Object> linkedHashMap = new LinkedHashMap<String,Object>(); boolean result = hashMap.getClass().isAssignableFrom( linkedHashMap.getClass() ); As LinkedHashMap is a subclass of HashMap this result variable will … Read more
Yes, you are guaranteed that whole numbers, including 0.0, compare with == Of course you have to be a little careful with how you got the whole number in the first place, assignment is safe but the result of any calculation is suspect ps there are a set of real numbers that do have a … Read more