Just .extend the collection with a meta data storage function. var MyCollection = Backbone.Collection.extend({ initialize: function() { … this._meta = {}; }, model: … meta: function(prop, value) { if (value === undefined) { return this._meta[prop] } else { this._meta[prop] = value; } }, }); var collection = new MyCollection(); collection.add(someModels); collection.meta(“someProperty”, value); … var value … Read more
It’s a way to remember that this class really implements that interface. It won’t have any bad effect and it can help to understand the code without going through the complete hierarchy of the given class.
Python <3.3 You mean something like this? class Record(object): __slots__= “attribute1”, “attribute2”, “attribute3”, def items(self): “dict style items” return [ (field_name, getattr(self, field_name)) for field_name in self.__slots__] def __iter__(self): “iterate over fields tuple/list style” for field_name in self.__slots__: yield getattr(self, field_name) def __getitem__(self, index): “tuple/list style getitem” return getattr(self, self.__slots__[index]) >>> r= Record() >>> r.attribute1= … Read more
The shortest way I’ve come up with is two statements: assertThat( affA.entrySet(), everyItem(isIn(affB.entrySet()))); assertThat( affB.entrySet(), everyItem(isIn(affA.entrySet()))); But you can probably also do: assertThat(affA.entrySet(), equalTo(affB.entrySet())); depending on the implementations of the maps, and sacrificing the clarity of the difference report: that would just tell you that there is a difference, while the statement above would also … Read more
You shouldn’t. a Collection avoids talking about indexes specifically because it might not make sense for the specific collection. For example, a List implies some form of ordering, but a Set does not. Collection<String> myCollection = new HashSet<String>(); myCollection.add(“Hello”); myCollection.add(“World”); for (String elem : myCollection) { System.out.println(“elem = ” + elem); } System.out.println(“myCollection.toArray()[0] = ” … Read more
It’s very easy to write that yourself, and that way you have more control over things.. As the other answers say, TypeScript is not aimed at adding runtime types or functionality. Map: class Map<T> { private items: { [key: string]: T }; constructor() { this.items = {}; } add(key: string, value: T): void { this.items[key] … Read more
Collections by themselves do not have a predefined order, therefore you must convert them to a java.util.List. Then you can use one form of java.util.Collections.sort Collection< T > collection = …; List< T > list = new ArrayList< T >( collection ); Collections.sort( list ); // or Collections.sort( list, new Comparator< T >( ){…} ); … Read more
To be correct, def data = [“a”,”b”,”c”] it is a List, not an array. Just try casting like this: def data = [“a”,”b”,”c”] as String[]
No, jQuery doesn’t, but Javascript does. Just use an object: var dict = { “1” : false, “2” : true, “3” : false }; // lookup: var second = dict[“2”]; // update: dict[“2”] = false; // add: dict[“4”] = true; // delete: delete dict[“2”];
You can do this widgets2.Where(y=>widget1.Any(z=>z.TypeID==y.TypeID));