You could use the substr function to return a substring starting from the 5th character: $str = “The quick brown fox jumps over the lazy dog.” $str2 = substr($str, 4); // “quick brown fox jumps over the lazy dog.”
You can use string.indexOf(‘a’). If the char a is present in string : it returns the the index of the first occurrence of the character in the character sequence represented by this object, or -1 if the character does not occur.
Vertical tab was used to speed up printer vertical movement. Some printers used special tab belts with various tab spots. This helped align content on forms. VT to header space, fill in header, VT to body area, fill in lines, VT to form footer. Generally it was coded in the program as a character constant. … Read more
Looping through the characters of a std::string, using a range-based for loop (it’s from C++11, already supported in recent releases of GCC, clang, and the VC11 beta): std::string str = ???; for(char& c : str) { do_things_with(c); } Looping through the characters of a std::string with iterators: std::string str = ???; for(std::string::iterator it = str.begin(); … Read more
LIKE ‘WC[[]R]S123456’ or LIKE ‘WC\[R]S123456’ ESCAPE ‘\’ Should work.
Swift 4.0 (also Swift 5.0) var str = “Hello, World” // “Hello, World” str.dropLast() // “Hello, Worl” (non-modifying) str // “Hello, World” String(str.dropLast()) // “Hello, Worl” str.remove(at: str.index(before: str.endIndex)) // “d” str // “Hello, Worl” (modifying) Swift 3.0 The APIs have gotten a bit more swifty, and as a result the Foundation extension has changed … Read more
Try this code: String str = “a12.334tyz.78x”; str = str.replaceAll(“[^\\d.]”, “”); Now str will contain “12.334.78”.
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The only thing that a computer can store is bytes. To store anything in a computer, you must first encode it, i.e. convert it to bytes. For example: If you want to store music, you must first encode it using MP3, WAV, etc. If you want to store a picture, you must first encode it … Read more
Try using the overload that takes CharSequence arguments (eg, String) rather than char: str = str.replace(“X”, “”);