Use isset() $matchFound = (isset($_GET[“id”]) && trim($_GET[“id”]) == ‘link1′); $slide = $matchFound ? trim($_GET[“id”]) : ”; EDIT: This is added for the completeness sake. $_GET in php is a reserved variable that is an associative array. Hence, you could also make use of ‘array_key_exists(mixed $key, array $array)’. It will return a boolean that the key … Read more
The following solution combines other answers and handles some special cases: The parameter does not exist in the original url The parameter is the only parameter The parameter is first or last The new parameter value is the same as the old The url ends with a ? character \b ensures another parameter ending with … Read more
You’ll want to construct a Uri and use that for the request. Something like final queryParameters = { ‘param1’: ‘one’, ‘param2’: ‘two’, }; final uri = Uri.https(‘www.myurl.com’, ‘/api/v1/test/${widget.pk}’, queryParameters); final response = await http.get(uri, headers: { HttpHeaders.authorizationHeader: ‘Token $token’, HttpHeaders.contentTypeHeader: ‘application/json’, }); See https://api.dartlang.org/stable/2.0.0/dart-core/Uri/Uri.https.html
The query component is indicated by the first ? in a URI. “Query string” might be a synonym (this term is not used in the URI standard). Some examples for HTTP URIs with query components: http://example.com/foo?bar http://example.com/foo/foo/foo?bar/bar/bar http://example.com/?bar http://example.com/?@bar._=???/1: http://example.com/?bar1=a&bar2=b (list of allowed characters in the query component) The “format” of the query component is … Read more
I think you want to turn any given URL string into a HASH? You can try http://www.ruby-doc.org/stdlib/libdoc/cgi/rdoc/classes/CGI.html#M000075 require ‘cgi’ CGI::parse(‘param1=value1¶m2=value2¶m3=value3’) returns {“param1″=>[“value1”], “param2″=>[“value2”], “param3″=>[“value3”]}
You can use the attribute prefix asp-route- to prefix your route variable names. Example: <a asp-controller=”Product” asp-action=”GetProduct” asp-route-id=”10″> ProductName</a>
Use urllib.parse.urlencode(). It takes a dictionary of key-value pairs, and converts it into a form suitable for a URL (e.g., key1=val1&key2=val2). For your example: >>> import urllib.parse >>> params = {‘a’:’A’, ‘b’:’B’} >>> urllib.parse.urlencode(params) ‘a=A&b=B’ If you want to make a URL with repetitive params such as: p=1&p=2&p=3 you have two options: >>> a = … Read more
I’ve extended Sujoy’s code to make up a function. /** * http://stackoverflow.com/a/10997390/11236 */ function updateURLParameter(url, param, paramVal){ var newAdditionalURL = “”; var tempArray = url.split(“?”); var baseURL = tempArray[0]; var additionalURL = tempArray[1]; var temp = “”; if (additionalURL) { tempArray = additionalURL.split(“&”); for (var i=0; i<tempArray.length; i++){ if(tempArray[i].split(‘=’)[0] != param){ newAdditionalURL += temp + … Read more
function getURLParameter(name) { return decodeURI( (RegExp(name + ‘=’ + ‘(.+?)(&|$)’).exec(location.search)||[,null])[1] ); }
In the year 2021… Please consider this obsolete. Edit This edit improves and explains the answer based on the comments. var search = location.search.substring(1); JSON.parse(‘{“‘ + decodeURI(search).replace(/”/g, ‘\\”‘).replace(/&/g, ‘”,”‘).replace(/=/g,'”:”‘) + ‘”}’) Example Parse abc=foo&def=%5Basf%5D&xyz=5 in five steps: decodeURI: abc=foo&def=[asf]&xyz=5 Escape quotes: same, as there are no quotes Replace &: abc=foo”,”def=[asf]”,”xyz=5 Replace =: abc”:”foo”,”def”:”[asf]”,”xyz”:”5 Suround with … Read more