The number itself is always interpreted as a non-negative number. Hexadecimal constants don’t have a sign or any inherent way to express a negative number. The type of the constant is the first one of these which can represent their value: int unsigned int long int unsigned long int long long int unsigned long long … Read more
In simple terms, if you mix types of the same rank (in the sequence of int, long int, long long int), the unsigned type “wins” and the calculations are performed within that unsigned type. The result is of the same unsigned type. If you mix types of different rank, the higher-ranked type “wins”, if it … Read more
import ctypes number = lv & 0xFFFFFFFF signed_number = ctypes.c_long(number).value
For the actual size of the pointer: size_t s = sizeof(unsigned char*); If you want the length of the string: unsigned char* bla = (unsigned char*)”blabla”; int s = strlen((char*)bla);
Your question is genuinely intriguing as the unsigned version consistently produces code that is 10 to 20% slower. Yet there are multiple problems in the code: Both functions return 0 for 2, 3, 5 and 7, which is incorrect. The test if (i != num) return 0; else return 1; is completely useless as the … Read more
C++ defines no such type as uint. This must be “your” type, i.e. a type defined in your code or some third party library. One can guess that it is the same as unsigned int. Could be unsigned long int though or something else. Anyway, you have to check it yourself. It is a matter … Read more
C# and the CLR have somewhat different conversion rules. You can’t directly cast between int[] and uint[] in C# because the language doesn’t believe any conversion is available. However, if you go via object the result is up to the CLI. From the CLI spec section 8.7 (I hope – I’m quoting an email exchange … Read more
C++ and C# are different languages. They have different rules for handling type promotion in the event of comparisons. In C++ and C, they’re usually compared as if they were both unsigned. This is called “unsigned preserving”. C++ and C compilers traditionally use “unsigned preserving” and the use of this is specified in the C++ … Read more
Let’s start by analysing the result of t – d. t is an unsigned int while d is an int, so to do arithmetic on them, the value of d is converted to an unsigned int (C++ rules say unsigned gets preference here). So we get 10u – 16u, which (assuming 32-bit int) wraps around … Read more
Using unsigned can introduce programming errors that are hard to spot, and it’s usually better to use signed int just to avoid them. One example would be when you decide to iterate backwards rather than forwards and write this: for (unsigned i = 5; i >= 0; i–) { printf(“%d\n”, i); } Another would be … Read more