You can use the substring function: let str = “12345.00”; str = str.substring(0, str.length – 1); console.log(str); This is the accepted answer, but as per the conversations below, the slice syntax is much clearer: let str = “12345.00”; str = str.slice(0, -1); console.log(str);
Since you cannot extend string.Trim(). You could make an Extension method as described here that trims and reduces whitespace. namespace CustomExtensions { //Extension methods must be defined in a static class public static class StringExtension { // This is the extension method. // The first parameter takes the “this” modifier // and specifies the type … Read more
UPDATE test SET log = REPLACE(REPLACE(log, ‘\r’, ”), ‘\n’, ”); worked for me. while its similar, it’ll also get rid of \r\n http://lists.mysql.com/mysql/182689
Or this can be solved with arrow functions: x.map(s => s.trim());
Do as below using String#tr : “((String1))”.tr(‘()’, ”) # => “String1”
Try this instead: if($.trim($(‘#group_field’).val()) != ”){ More Info: http://api.jquery.com/jQuery.trim/
Try string.TrimEnd(): Something = Something.TrimEnd(‘,’);
All of them. Returns: A copy of this string with leading and trailing white space removed, or this string if it has no leading or trailing white space. ~ Quoted from Java 1.5.0 docs (But why didn’t you just try it and see for yourself?)
Starting from Xcode 4.4 whitespaces will be trimmed automatically by default, unless the line is all whitespace. You can also activate Including whitespace-only lines to fix this, which is not active by default. Go to Xcode > Preferences > Text Editing > While editing
EDIT Since c++17, some parts of the standard library were removed. Fortunately, starting with c++11, we have lambdas which are a superior solution. #include <algorithm> #include <cctype> #include <locale> // trim from start (in place) static inline void ltrim(std::string &s) { s.erase(s.begin(), std::find_if(s.begin(), s.end(), [](unsigned char ch) { return !std::isspace(ch); })); } // trim from … Read more