With a regex you could write: String s = … String ltrim = s.replaceAll(“^\\s+”,””); String rtrim = s.replaceAll(“\\s+$”,””); If you have to do it often, you can create and compile a pattern for better performance: private final static Pattern LTRIM = Pattern.compile(“^\\s+”); public static String ltrim(String s) { return LTRIM.matcher(s).replaceAll(“”); } From a performance perspective, … Read more
Problem The trim() method removes whitespace from both sides of a string. Source Solution You can use a Javascript replace method to remove white space like “hello world”.replace(/\s/g, “”); Example var out = “hello world”.replace(/\s/g, “”); console.log(out);
Another possible option (that avoids LINQ, for better or worse): string line = ” abc, foo , bar”; string[] parts= Array.ConvertAll(line.Split(‘,’), p => p.Trim()); However, if you just need to know if it is there – perhaps short-circuit? bool contains = line.Split(‘,’).Any(p => p.Trim() == match);
You could use Leading: System.out.println(“//test/me”.replaceAll(“^/+”, “”)); Trailing: System.out.println(“//test/me//”.replaceAll(“/+$”, “”));
If you have serious text processing needs then use the text package from hackage: > :set -XOverloadedStrings > import Data.Text > strip ” abc ” “abc” If you’re too stubborn to use text and don’t like the inefficiency of the reverse method then perhaps (and I mean MAYBE) something like the below will be more … Read more
jQuery.trim() capital Q? or $.trim() Edit (2021): This answer is 11 years old (2010). There are better solutions posted below.
You’re close. Remember that replace replaces the found text with the second argument. So: newString = string.replace(/\s+/g,”); // “thiscontainsspaces” Finds any number of sequential spaces and removes them. Try replacing them with a single space instead! newString = string.replace(/\s+/g,’ ‘).trim();
Apache Commons has a great StringUtils class (org.apache.commons.lang.StringUtils). In StringUtils there is a strip(String, String) method that will do what you want. I highly recommend using Apache Commons anyway, especially the Collections and Lang libraries.
Using a combination of SUBSTR, INSTR, and NVL (for strings without an underscore) will return what you want: SELECT NVL(SUBSTR(‘ABC_blah’, 0, INSTR(‘ABC_blah’, ‘_’)-1), ‘ABC_blah’) AS output FROM DUAL Result: output —— ABC Use: SELECT NVL(SUBSTR(t.column, 0, INSTR(t.column, ‘_’)-1), t.column) AS output FROM YOUR_TABLE t Reference: SUBSTR INSTR Addendum If using Oracle10g+, you can use regex … Read more
String input = EditTextinput.getText().toString(); input = input.replace(” “, “”); Sometimes you would want to remove only the spaces at the beginning or end of the String (not the ones in the middle). If that’s the case you can use trim: input = input.trim();