How about Morris Inorder tree traversal? Its based on the notion of threaded trees and it modifies the tree, but reverts it back when its done. Linkie: http://geeksforgeeks.org/?p=6358 Doesn’t use any extra space.
The best way is to use the node object directly by using its attributes property. The only difference in my solution below compared to others suggesting this method is that i would use .each again instead of a traditional js loop: $(xml).find(‘item’).each(function() { $.each(this.attributes, function(i, attrib){ var name = attrib.name; var value = attrib.value; // … Read more
Here’s a fully parametric example: data Weird a = Weird a (a -> a) instance Foldable Weird where foldMap f (Weird a b) = f $ b a Weird is not a Functor because a occurs in a negative position.
Two methods in particular would be very useful solving this problem: .nextUntil, and .andSelf. The first will grab all of the siblings following your selector, and the latter will lump in whatever is matched by your selector as well, giving you one jQuery object that includes them all: $(“#heading2”) .nextUntil(“#heading3”).andSelf() .css(“background”, “red”); This results in … Read more
Both are valid DFS algorithms. A DFS does not specify which node you see first. It is not important because the order between edges is not defined [remember: edges are a set usually]. The difference is due to the way you handle each node’s children. In the iterative approach: You first insert all the elements … Read more
Here’s the version with one stack and without a visited flag: private void postorder(Node head) { if (head == null) { return; } LinkedList<Node> stack = new LinkedList<Node>(); stack.push(head); while (!stack.isEmpty()) { Node next = stack.peek(); boolean finishedSubtrees = (next.right == head || next.left == head); boolean isLeaf = (next.left == null && next.right == … Read more
No need for jQuery. JavaScript arrays have a find method, so you can achieve that in one line: array.find((o) => { return o[propertyName] === propertyValue }) Example const purposeObjects = [ {purpose: “daily”}, {purpose: “weekly”}, {purpose: “monthly”} ]; purposeObjects.find((o) => { return o[“purpose”] === “weekly” }) // output -> {purpose: “weekly”} If you need IE … Read more
I found this Q/A very interesting, since it provides several different solutions for the same problem. I took all these functions and tested them with a complex dictionary object. I had to take two functions out of the test, because they had to many fail results and they did not support returning lists or dicts … Read more
traverse is the same as fmap, except that it also allows you to run effects while you’re rebuilding the data structure. Take a look at the example from the Data.Traversable documentation. data Tree a = Empty | Leaf a | Node (Tree a) a (Tree a) The Functor instance of Tree would be: instance Functor … Read more
Try: $(‘li.current_sub’).prevAll(“li.par_cat:first”); Tested it with your markup: $(‘li.current_sub’).prevAll(“li.par_cat:first”).text(“woohoo”); <script src=”https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js”></script> <ul> <li class=”par_cat”></li> <li class=”sub_cat”></li> <li class=”sub_cat”></li> <li class=”par_cat”>// this is the single element I need to select</li> <li class=”sub_cat”></li> <li class=”sub_cat”></li> <li class=”sub_cat current_sub”>// this is where I need to start searching</li> <li class=”par_cat”></li> <li class=”sub_cat”></li> <li class=”par_cat”></li> </ul> will fill up the closest … Read more