Simple check to see if two time periods overlap: bool overlap = a.start < b.end && b.start < a.end; or in your code: bool overlap = tStartA < tEndB && tStartB < tEndA; (Use <= instead of < if you change your mind about wanting to say that two periods that just touch each other … Read more
You can use the date function: date(“Y-m-d H:i:s”);
Since C++ 11 you can use std::chrono::system_clock::now() Example (copied from en.cppreference.com): #include <iostream> #include <chrono> #include <ctime> int main() { auto start = std::chrono::system_clock::now(); // Some computation here auto end = std::chrono::system_clock::now(); std::chrono::duration<double> elapsed_seconds = end-start; std::time_t end_time = std::chrono::system_clock::to_time_t(end); std::cout << “finished computation at ” << std::ctime(&end_time) << “elapsed time: ” << elapsed_seconds.count() << … Read more
PowerShell has a cmdlet for this called Measure-Command. You’ll have to ensure that PowerShell is available on the machine that runs it. PS> Measure-Command { echo hi } Days : 0 Hours : 0 Minutes : 0 Seconds : 0 Milliseconds : 0 Ticks : 1318 TotalDays : 1.52546296296296E-09 TotalHours : 3.66111111111111E-08 TotalMinutes : 2.19666666666667E-06 … Read more
.getMonth() returns a zero-based number so to get the correct month you need to add 1, so calling .getMonth() in may will return 4 and not 5. So in your code we can use currentdate.getMonth()+1 to output the correct value. In addition: .getDate() returns the day of the month <- this is the one you … Read more
The T is just a literal to separate the date from the time, and the Z means “zero hour offset” also known as “Zulu time” (UTC). If your strings always have a “Z” you can use: SimpleDateFormat format = new SimpleDateFormat( “yyyy-MM-dd’T’HH:mm:ss.SSS’Z'”, Locale.US); format.setTimeZone(TimeZone.getTimeZone(“UTC”)); Or using Joda Time, you can use ISODateTimeFormat.dateTime().
Use the java.util.concurrent.TimeUnit class: String.format(“%d min, %d sec”, TimeUnit.MILLISECONDS.toMinutes(millis), TimeUnit.MILLISECONDS.toSeconds(millis) – TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)) ); Note: TimeUnit is part of the Java 1.5 specification, but toMinutes was added as of Java 1.6. To add a leading zero for values 0-9, just do: String.format(“%02d min, %02d sec”, TimeUnit.MILLISECONDS.toMinutes(millis), TimeUnit.MILLISECONDS.toSeconds(millis) – TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)) ); If TimeUnit or toMinutes are unsupported … Read more
The time.time() function returns the number of seconds since the epoch, as a float. Note that “the epoch” is defined as the start of January 1st, 1970 in UTC. So the epoch is defined in terms of UTC and establishes a global moment in time. No matter where on Earth you are, “seconds past epoch” … Read more
Using time.time(): import time def current_milli_time(): return round(time.time() * 1000) Then: >>> current_milli_time() 1378761833768
Use weekday(): >>> import datetime >>> datetime.datetime.today() datetime.datetime(2012, 3, 23, 23, 24, 55, 173504) >>> datetime.datetime.today().weekday() 4 From the documentation: Return the day of the week as an integer, where Monday is 0 and Sunday is 6.