How to check if a subclass is an instance of a class at runtime? [duplicate]

You have to read the API carefully for this methods. Sometimes you can get confused very easily. It is either: if (B.class.isInstance(view)) API says: Determines if the specified Object (the parameter) is assignment-compatible with the object represented by this Class (The class object you are calling the method at) or: if (B.class.isAssignableFrom(view.getClass())) API says: Determines … Read more

Getting the name of a sub-class from within a super-class

Don’t make the method static. The issue is that when you invoke getClass() you are calling the method in the super class – static methods are not inherited. In addition, you are basically name-shadowing Object.getClass(), which is confusing. If you need to log the classname within the superclass, use return this.getClass().getName(); This will return “Entity” … Read more

When do you need to explicitly call a superclass constructor?

You never need just super(); That’s what will be there if you don’t specify anything else. You only need to specify the constructor to call if: You want to call a superclass constructor which has parameters You want to chain to another constructor in the same class instead of the superclass constructor You claim that: … Read more

How do I check if an object’s type is a particular subclass in C++?

  class Base { public: virtual ~Base() {} }; class D1: public Base {}; class D2: public Base {}; int main(int argc,char* argv[]); { D1 d1; D2 d2; Base* x = (argc > 2)?&d1:&d2; if (dynamic_cast<D2*>(x) == nullptr) { std::cout << “NOT A D2” << std::endl; } if (dynamic_cast<D1*>(x) == nullptr) { std::cout << “NOT … Read more

Abstract classes in Swift Language

There are no abstract classes in Swift (just like Objective-C). Your best bet is going to be to use a Protocol, which is like a Java Interface. With Swift 2.0, you can then add method implementations and calculated property implementations using protocol extensions. Your only restrictions are that you can’t provide member variables or constants … Read more

Why aren’t superclass __init__ methods automatically invoked?

The crucial distinction between Python’s __init__ and those other languages constructors is that __init__ is not a constructor: it’s an initializer (the actual constructor (if any, but, see later;-) is __new__ and works completely differently again). While constructing all superclasses (and, no doubt, doing so “before” you continue constructing downwards) is obviously part of saying … Read more

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