String.Split takes an array when including any StringSplitOptions: string[] batchstring = batch_idTextBox.Text.Split(new [] { ‘;’ }, StringSplitOptions.RemoveEmptyEntries); If you don’t need options, the syntax becomes easier: string[] batchstring = batch_idTextBox.Text.Split(‘;’);
string valueStr = “title, genre, director, actor”; var vals = valueStr.Split(‘,’)[0]; vals will give you the title
I was slightly surprised that split() performed so badly in your code, so I looked at it a bit more closely and noticed that you’re calling list.remove() in the inner loop. Also you’re calling split() an extra time on each string. Get rid of those and a solution using split() beats the regex hands down … Read more
When using “\t”, the escape sequence \t is replaced by Java with the character U+0009. When using “\\t”, the escape sequence \\ in \\t is replaced by Java with \, resulting in \t that is then interpreted by the regular expression parser as the character U+0009. So both notations will be interpreted correctly. It’s just … Read more
Regex lineSplitter = new Regex(@”[\s*\*]*\|[\s*\*]*”); var columns = lineSplitter.Split(data).Where(s => s != String.Empty); or you could simply do: string[] columns = data.Split(new char[] {‘|’}, StringSplitOptions.RemoveEmptyEntries); foreach (string c in columns) this.textBox1.Text += “[” + c.Trim(‘ ‘, ‘*’) + “] ” + “\r\n”; And no, there is no option to remove empty entries for RegEx.Split as … Read more
It does. However split(…) returns an array, it does not “transform” your String into a String[]. Try this: String expression = “1+2+10+1”; String[] tokens = expression.split(“\\+”);
There is no need to escape forward slashes. Your code works fine if you just do: String[] paths = path.split(“https://stackoverflow.com/”);