strings.LastIndex makes this quite neat: s := “Hello,Stack,Overflow” last := s[strings.LastIndex(s, “,”)+1:] fmt.Println(last) returns “Overflow”. If the search string isn’t found it returns the whole string, which is logical. Playground here
Using the colon in an indexing operation generates a slice object, which is not hashable.
You can instead try using: word[1:]
a[i] = i simply assigns the value i to a[i]. This is not appending, it’s just a simple assignment. Now the append: a = append(a, i) In theory the following happens: This calls the builtin append() function. For that, it first has to copy the a slice (slice header, backing array is not part of … Read more
This: x[:, 1] means “take all indices of x along the first axis, but only index 1 along the second”. This: x[:][1] means “take all indices of x along the first axis (so all of x), then take index 1 along the first axis of the result”. You’re applying the 1 to the wrong axis. … Read more
If you have set the “Timestamp” column as the index , then you can simply use df[‘2009-05-01′ :’2010-03-01’]
The simplest solution with a loop would look like this: func memsetLoop(a []int, v int) { for i := range a { a[i] = v } } There is no memset support in the standard library, but we can make use of the built-in copy() which is highly optimized. With repeated copy() We can set … Read more
Simply use the hex.DecodeString() function: s := “46447381” data, err := hex.DecodeString(s) if err != nil { panic(err) } fmt.Printf(“% x”, data) Output: 46 44 73 81 Try it on the Go Playground. Note: If you just simply print the byte slice using fmt.Println(data), the printed values will be in decimal format that’s why it … Read more
Use a for loop: elements = []string{“abc”, “def”, “fgi”, “adi”} elementMap := make(map[string]string) for i := 0; i < len(elements); i +=2 { elementMap[elements[i]] = elements[i+1] } runnable example on the playground The standard library does not have a function to do this.