You will definitely want to start with a good web scraping framework. Later on, you may decide that they are too limiting and you can put together your own stack of libraries but without a lot of scraping experience, your design will be much worse than pjscrape or scrapy. Note: I use the terms crawling … Read more
You are so close to answering this yourself that I am somewhat reluctant to answer it for you. However, the following XPath should provide what you want (provided the source is XHTML, of course). //img[@class=”photo-large”]/@src For further tips, check out W3 Schools. They have excellent tutorials on such things and a great reference too.
You can’t prevent it.
I agree that the Scrapy docs give off that impression. But, I believe, as I found for myself, that if you are patient with Scrapy, and go through the tutorials first, and then bury yourself into the rest of the documentation, you will not only start to understand the different parts to Scrapy better, but … Read more
You can use selenium to scrap the infinite scrolling website like twitter or facebook. Step 1 : Install Selenium using pip pip install selenium Step 2 : use the code below to automate infinite scroll and extract the source code from selenium import webdriver from selenium.webdriver.common.by import By from selenium.webdriver.common.keys import Keys from selenium.webdriver.support.ui import … Read more
I’m currently using this: String content = null; URLConnection connection = null; try { connection = new URL(“http://www.google.com”).openConnection(); Scanner scanner = new Scanner(connection.getInputStream()); scanner.useDelimiter(“\\Z”); content = scanner.next(); scanner.close(); }catch ( Exception ex ) { ex.printStackTrace(); } System.out.println(content); But not sure if there’s a better way.
When you download a file with urllib or urllib2, you can find out whether a charset header was transmitted: fp = urllib2.urlopen(request) charset = fp.headers.getparam(‘charset’) You can use BeautifulSoup to locate a meta element in the HTML: soup = BeatifulSoup.BeautifulSoup(data) meta = soup.findAll(‘meta’, {‘http-equiv’:lambda v:v.lower()==’content-type’}) If neither is available, browsers typically fall back to user … Read more
.findAll() works for nested li elements: for ul in uls: for li in ul.findAll(‘li’): print(li) Output: <li>List items</li> <li>Etc…</li> <li>List items</li> <li>Nested list items</li> <li>Nested list items</li> <li>List items</li>