scanf (and cousins) have one slightly strange characteristic: white space in (most placed in) the format string matches an arbitrary amount of white space in the input. As it happens, at least in the default “C” locale, a new-line is classified as white space. This means the trailing ‘\n’ is trying to match not only … Read more
How come %d is deprecated? It seem that all int specifiers are deprecated. They are not deprecated in the sense that that term is ordinarily used in software documentation. There is no plan for their removal from the language and there are no direct replacements. The ISO committee responsible for maintaining the language standard has … Read more
*c means, that a char will be read but won’t be assigned, for example for the input “30a” it will assign 30 to word_count, but ‘a’ will be ignored.
You take scanf(). You throw it in the bin. You use fgets() to get an entire line. You use strtol() to parse the line as an integer, checking if it consumed the entire line. char *end; char buf[LINE_MAX]; do { if (!fgets(buf, sizeof buf, stdin)) break; // remove \n buf[strlen(buf) – 1] = 0; int … Read more
Try: while(scanf(“%15s”, words) != EOF) You need to compare scanf output with EOF Since you are specifying a width of 15 in the format string, you’ll read at most 15 char. So the words char array should be of size 16 ( 15 +1 for null char). So declare it as: char words[16];
I think by default values read by scanf with space/enter. Well you can provide space between ‘%d’ if you are printing integers. Also same for other cases. scanf(“%d %d %d”, &var1, &var2, &var3); Similarly if you want to read comma separated values use : scanf(“%d,%d,%d”, &var1, &var2, &var3);
sscanf() converts the string you pass in to an _IO_FILE* to make the string look like a “file”. This is so the same internal _IO_vfscanf() can be used for both a string and a FILE*. However, as part of that conversion, done in a _IO_str_init_static_internal() function, it calls __rawmemchr (ptr, ‘\0’); essentially a strlen() call, … Read more
When a variable is defined, the compiler allocates memory for that variable. int i; // The compiler will allocate sizeof(int) bytes for i i defined above is not initialized and have indeterminate value. To write data to that memory location allocated for i, you need to specify the address of the variable. The statement scanf(“%d”, … Read more
Since the files are “semi-structured” can’t you use a combination of ReadLine() and TryParse() methods, or the Regex class to parse your data?
It is a function that belongs specifically to the Microsoft compiler. scanf originally just reads whatever console input you type and assign it to a type of variable. If you have an array called first_name[5] and you use scanf for “Alex”, there is no problem. If you have the same array and assign “Alexander”, you … Read more