This example shows the differences between adding a method to a class and to an instance. >>> class Dog(): … def __init__(self, name): … self.name = name … >>> skip = Dog(‘Skip’) >>> spot = Dog(‘Spot’) >>> def talk(self): … print ‘Hi, my name is ‘ + self.name … >>> Dog.talk = talk # add … Read more
I just did this last week. Set the GrowStyle on the TableLayoutPanel to AddRows or AddColumns, then your code should work: // Adds “myControl” to the first column of each row myTableLayoutPanel.Controls.Add(myControl1, 0 /* Column Index */, 0 /* Row index */); myTableLayoutPanel.Controls.Add(myControl2, 0 /* Column Index */, 1 /* Row index */); myTableLayoutPanel.Controls.Add(myControl3, 0 … Read more
You need to use WebConfigurationManager.OpenWebConfiguration(): For Example: Dim myConfiguration As Configuration = System.Web.Configuration.WebConfigurationManager.OpenWebConfiguration(“~”) myConfiguration.ConnectionStrings.ConnectionStrings(“myDatabaseName”).ConnectionString = txtConnectionString.Text myConfiguration.AppSettings.Settings.Item(“myKey”).Value = txtmyKey.Text myConfiguration.Save() I think you might also need to set AllowLocation in machine.config. This is a boolean value that indicates whether individual pages can be configured using the element. If the “allowLocation” is false, it cannot be … Read more
Is there a way to initialize the EntityManager without a persistence unit defined? You should define at least one persistence unit in the persistence.xml deployment descriptor. Can you give all the required properties to create an Entitymanager? The name attribute is required. The other attributes and elements are optional. (JPA specification). So this should be … Read more
Edit: I want to point out to people coming here from searches that this question is specifically dealing with non-class types, ie object shapes as defined by interface or type alias. For class types you can use JavaScript’s instanceof to determine the class an instance comes from, and TypeScript will narrow the type in the … Read more
The Java API documentation explains why (http://java.sun.com/javase/6/docs/api/java/lang/Class.html#newInstance()): Note that this method propagates any exception thrown by the nullary constructor, including a checked exception. Use of this method effectively bypasses the compile-time exception checking that would otherwise be performed by the compiler. The Constructor.newInstance method avoids this problem by wrapping any exception thrown by the constructor … Read more
You can use Context.checkCallingorSelfPermission() function for this. Here is an example: private boolean checkWriteExternalPermission() { String permission = android.Manifest.permission.WRITE_EXTERNAL_STORAGE; int res = getContext().checkCallingOrSelfPermission(permission); return (res == PackageManager.PERMISSION_GRANTED); }
Compile-time dependency: You need the dependency in your CLASSPATH to compile your artifact. They are produced because you have some kind of “reference” to the dependency hardcoded in your code, such as calling new for some class, extending or implementing something (either directly or indirectly), or a method call using the direct reference.method() notation. Run-time … Read more
time.in_time_zone(time_zone) Example: zone = ActiveSupport::TimeZone.new(“Central Time (US & Canada)”) Time.now.in_time_zone(zone) or just Time.now.in_time_zone(“Central Time (US & Canada)”) You can find the names of the ActiveSupport time zones by doing: ActiveSupport::TimeZone.all.map(&:name) # or for just US ActiveSupport::TimeZone.us_zones.map(&:name)
A compile-time dependency is generally required at runtime. In maven, a compile scoped dependency will be added to the classpath on runtime (e.g. in wars they will be copied to WEB-INF/lib). It is not, however, strictly required; for instance, we may compile against a certain API, making it a compile-time dependency, but then at runtime … Read more