Looking for a replace-in-string function in elisp
Try this: (defun replace-in-string (what with in) (replace-regexp-in-string (regexp-quote what) with in nil ‘literal))
Try this: (defun replace-in-string (what with in) (replace-regexp-in-string (regexp-quote what) with in nil ‘literal))
collection[someIndex] = newItem;
While using regular expressions imparts some performance impact, it should not be as terrible. Note that using String.replaceAll() will compile the regular expression each time you call it. You can avoid that by explicitly using a Pattern object: Pattern p = Pattern.compile(“[,. ]+”); // repeat only the following part: String output = p.matcher(input).replaceAll(“”); Note also … Read more
Yes, there exists better way: def print_dict(d): new = {} for k, v in d.iteritems(): if isinstance(v, dict): v = print_dict(v) new[k.replace(‘.’, ‘-‘)] = v return new (Edit: It’s recursion, more on Wikipedia.)
You can use the “Find and Replace” feature of Visual Studio to delete matching lines. The key is to match the whole line including the end of line character as well. You can do this in wildcard or regular expression mode. In wildcard mode, begin the expression with * and end the expression with *\n. … Read more
Does replacing a character in a String with a null character even work in Java? I know that ‘\0’ will terminate a c-string. That depends on how you define what is working. Does it replace all occurrences of the target character with ‘\0’? Absolutely! String s = “food”.replace(‘o’, ‘\0’); System.out.println(s.indexOf(‘\0’)); // “1” System.out.println(s.indexOf(‘d’)); // “3” … Read more
You can solve this by using Visual Studio temporary macros. This is a very powerful, flexible feature which I use all the time for performing repetitive code manipulations. I’m assuming you’re using the C# default key bindings here. Press CTRL+SHIFT+F to bring up the find in files dialogue. Click use “Regular expressions” Set “Find what:” … Read more
Search for: , Replace by: =>”iiii”,\n DO NOT FORGET to check Regex option (as shown on 1st screenshot below) Hit “Replace all” button BEFORE: AFTER:
The backslash is an escape character, so if you want to specify the actual backslash character in a string literal, you need to use two backslashes. NSString *new = [old stringByReplacingOccurrencesOfString: @”\\u0153″ withString:@”oe”];