What about DataFrame.replace? In [9]: mapping = {‘set’: 1, ‘test’: 2} In [10]: df.replace({‘set’: mapping, ‘tesst’: mapping}) Out[10]: Unnamed: 0 respondent brand engine country aware aware_2 aware_3 age \ 0 0 a volvo p swe 1 0 1 23 1 1 b volvo None swe 0 0 1 45 2 2 c bmw p us … Read more
You can get the list of correspondances character => entity used by htmlentities, with the function get_html_translation_table ; consider this code : $list = get_html_translation_table(HTML_ENTITIES); var_dump($list); (You might want to check the second parameter to that function in the manual — maybe you’ll need to set it to a value different than the default one) … Read more
For example, you could do: String result = input.split(“-“)[0]; or String result = input.substring(0, input.indexOf(“-“)); (and add relevant error handling)
UPDATE: There are a couple of paragraph-level functions that do a good job of this and can be found on the GitHub site for python-docx. This one will replace a regex-match with a replacement str. The replacement string will appear formatted the same as the first character of the matched string. This one will isolate … Read more
I’ve decided to use ack and perl to solve this problem outside of Vim so I could use the more powerful Perl regular expressions instead of the GNU subset. You could map this to a key stroke in your .vimrc. ack -l ‘pattern’ | xargs perl -pi -E ‘s/pattern/replacement/g’ Explanation ack ack is an awesome … Read more
Try M-x query-replace-regexp with “<\([^>]+\)>” as the search string and “<\,(downcase \1)>” as the replacement. This should work for Emacs 22 and later, see this Steve Yegge blog post for more details on how Lisp expressions can be used in the replacement string. For earlier versions of Emacs you could try something like this: (defun … Read more
Replace all occurrences of str1 with str2 in certain line: :s/str1/str2/g remove the g option if you want to replace only the first occurrence.
For an ‘easy’ alternative just use a StringBuilder…. StringBuilder sb = new StringBuilder(“11223344”); string myString = sb .Replace(“1”, string.Empty) .Replace(“2”, string.Empty) .Replace(“3”, string.Empty) .ToString();
Instead of “$2 $1”, you can use “${secondMatch} ${firstMatch}”. There is a list of all the replacements you can do here. Here is an abbreviated list: $number – The captured group by number. ${name} – The captured group by name. $$ – $ literal. $& – Entire match. $` – The input string before the … Read more
If your regex version supports it, you can use \L, like so in a POSIX shell: sed -r ‘s/(^.*)/\L\1/’