Your replace format is off In [21]: df = pd.DataFrame({‘a’:[‘Small’, ‘Medium’, ‘High’]}) In [22]: df Out[22]: a 0 Small 1 Medium 2 High [3 rows x 1 columns] In [23]: df.replace({‘a’ : { ‘Medium’ : 2, ‘Small’ : 1, ‘High’ : 3 }}) Out[23]: a 0 1 1 2 2 3 [3 rows x 1 … Read more
Use replace In [126]: df.replace([‘very bad’, ‘bad’, ‘poor’, ‘good’, ‘very good’], [1, 2, 3, 4, 5]) Out[126]: resp A B C 0 1 3 3 4 1 2 4 3 4 2 3 5 5 5 3 4 2 3 2 4 5 1 1 1 5 6 3 4 1 6 7 4 4 … Read more
re.sub() has a count parameter that indicates how many substitutions to perform. You can just set that to 1: >>> s = “foo foo foofoo foo” >>> re.sub(“foo”, “bar”, s, 1) ‘bar foo foofoo foo’ >>> s = “baz baz foo baz foo baz” >>> re.sub(“foo”, “bar”, s, 1) ‘baz baz bar baz foo baz’ … Read more
Try: name = “^aH^ai” name = name:gsub(“%^a”, “”) See also: http://lua-users.org/wiki/StringLibraryTutorial
Hi usually when working with Javascript I use the json module provided by Python. It will escape the string as well as a bunch of other things as user2357112 has pointed out. import json string = ‘This sentence has some “quotes” in it\n’ json.dumps(string) #gives you ‘”This sentence has some \\”quotes\\” in it\\n”‘
The following code should replace the last occurrence of a ‘,’ with a ‘)’. StringBuilder b = new StringBuilder(yourString); b.replace(yourString.lastIndexOf(“,”), yourString.lastIndexOf(“,”) + 1, “)” ); yourString = b.toString(); Note This will throw Exceptions if the String doesn’t contain a ‘,’.
You can use regular expressions if you prepare the search string. In PHP e.g. there is a function preg_quote, which replaces all regex-chars in a string with their escaped versions. Here is such a function for javascript (source): function preg_quote (str, delimiter) { // discuss at: https://locutus.io/php/preg_quote/ // original by: booeyOH // improved by: Ates … Read more
A MatchEvaluator is a delegate that takes a Match object and returns a string that should be replaced instead of the match. You can also refer to groups from the match. You can rewrite your code as follows: string input = “23x * y34x2″; Regex reg = new Regex(@”\d(?=[a-z])|[a-z](?=\d)”); string result = reg.Replace(input, delegate(Match m) … Read more
M-x replace-string C-q C-j RET RET The trick is to quote the C-j with C-q, but otherwise replacing newlines is like replacing anything else.
Sed (stream editor for filtering and transforming text) is your friend. sed -i ‘s/old text/new text/g’ file Sed performs text transformations in a single pass.