Using unsafe and compiled as x64 result: Implementation | Exec | GC #1 Simple | 4706ms | 0ms #2 Simple parallel | 2265ms | 0ms #3 ParallelSubstring | 800ms | 21ms #4 Fredou unsafe | 432ms | 15ms take the code of Erti-Chris Eelmaa and replace my previous one with this. I don’t think I … Read more
In VIM: :g!/^[+-]/d Here is the English translation: globally do something to all lines that do NOT! match the regular expression: start of line^ followed by either + or -, and that something to do is to delete those lines.
I think in Visual Studio, you can mark expressions with curly braces {txtSomeNum.Text}. Then in the replacement, you can refer to it with \1. So the replacement line would be something like Int32.Parse(\1). Update: via @Timothy003 VS 11 does away with the {} \1 syntax and uses () $1
Using np.where is faster. Using a similar pattern as you used with replace: df[‘col1’] = np.where(df[‘col1’] == 0, df[‘col2’], df[‘col1’]) df[‘col1’] = np.where(df[‘col1’] == 0, df[‘col3’], df[‘col1’]) However, using a nested np.where is slightly faster: df[‘col1’] = np.where(df[‘col1’] == 0, np.where(df[‘col2’] == 0, df[‘col3’], df[‘col2’]), df[‘col1’]) Timings Using the following setup to produce a larger … Read more
String.gsub should do the trick. Quoting docs: gsub(pattern, replacement) → new_str Returns a copy of str with the all occurrences of pattern substituted for the second argument. The pattern is typically a Regexp; if given as a String, any regular expression metacharacters it contains will be interpreted literally, e.g. \\d will match a backlash followed … Read more
I have found that the easiest and best way to remove all escape characters from your JSON string, is to pass the string into Regex.Unescape() method. This method returns a new string with no ecapes, even \n \t etc, are removed. See this MSDN article for more details: Regex.Unescape Method (String) (System.Text.RegularExpressions)
If the data is tokenized (i.e. “Dear $name$, as of $date$ your balance is $amount$”), then a Regex can be useful: static readonly Regex re = new Regex(@”\$(\w+)\$”, RegexOptions.Compiled); static void Main() { string input = @”Dear $name$, as of $date$ your balance is $amount$”; var args = new Dictionary<string, string>( StringComparer.OrdinalIgnoreCase) { {“name”, “Mr … Read more
You just need to daisy-chain them: REPLACE(REPLACE(T2.[ShipToCode], ‘&’, ‘and’), ‘,’, ”)
It looks like you want to use a template. //Updated 28 October 2011: Now allows 0, NaN, false, null and undefined in output. function template( templateid, data ){ return document.getElementById( templateid ).innerHTML .replace( /%(\w*)%/g, // or /{(\w*)}/g for “{this} instead of %this%” function( m, key ){ return data.hasOwnProperty( key ) ? data[ key ] : … Read more