From here download this video so we have the same video file for the test. Make sure to have that mp4 file in the same directory of your python code. Then also make sure to run the python interpreter from the same directory. Then modify the code, ditch waitKey that’s wasting time also without a … Read more
In Python 2 >>> plain_string = “Hi!” >>> unicode_string = u”Hi!” >>> type(plain_string), type(unicode_string) (<type ‘str’>, <type ‘unicode’>) ^ This is the difference between a byte string (plain_string) and a unicode string. >>> s = “Hello!” >>> u = unicode(s, “utf-8”) ^ Converting to unicode and specifying the encoding. In Python 3 All strings are … Read more
Python’s built-in CSV module can handle this easily: import csv with open(“output.csv”, “wb”) as f: writer = csv.writer(f) writer.writerows(a) This assumes your list is defined as a, as it is in your question. You can tweak the exact format of the output CSV via the various optional parameters to csv.writer() as documented in the library … Read more
Option: isoformat() Python’s datetime does not support the military timezone suffixes like ‘Z’ suffix for UTC. The following simple string replacement does the trick: In [1]: import datetime In [2]: d = datetime.datetime(2014, 12, 10, 12, 0, 0) In [3]: str(d).replace(‘+00:00’, ‘Z’) Out[3]: ‘2014-12-10 12:00:00Z’ str(d) is essentially the same as d.isoformat(sep=’ ‘) See: Datetime, … Read more
Use the first; it directly tries to check if something is defined in environ. Though the second form works equally well, it’s lacking semantically since you get a value back if it exists and only use it for a comparison. You’re trying to see if something is present in environ, why would you get just … Read more
This might happen inside scikit, and it depends on what you’re doing. I recommend reading the documentation for the functions you’re using. You might be using one which depends e.g. on your matrix being positive definite and not fulfilling that criteria. EDIT: How could I miss that: np.isnan(mat.any()) #and gets False np.isfinite(mat.all()) #and gets True … Read more
Seems you forgot the ” of your string. In [43]: df[‘Value’] = df.apply(lambda row: my_test(row[‘a’], row[‘c’]), axis=1) In [44]: df Out[44]: a b c Value 0 -1.674308 foo 0.343801 0.044698 1 -2.163236 bar -2.046438 -0.116798 2 -0.199115 foo -0.458050 -0.199115 3 0.918646 bar -0.007185 -0.001006 4 1.336830 foo 0.534292 0.268245 5 0.976844 bar -0.773630 -0.570417 … Read more
import pandas as pd pd.options.display.float_format=”${:,.2f}”.format df = pd.DataFrame([123.4567, 234.5678, 345.6789, 456.7890], index=[‘foo’,’bar’,’baz’,’quux’], columns=[‘cost’]) print(df) yields cost foo $123.46 bar $234.57 baz $345.68 quux $456.79 but this only works if you want every float to be formatted with a dollar sign. Otherwise, if you want dollar formatting for some floats only, then I think you’ll have … Read more
Solution Since Python 3, input returns a string which you have to explicitly convert to ints, with int, like this x = int(input(“Enter a number: “)) y = int(input(“Enter a number: “)) You can accept numbers of any base and convert them directly to base-10 with the int function, like this >>> data = int(input(“Enter … Read more
I’d say chunks = [data[x:x+100] for x in range(0, len(data), 100)] If you are using python 2.x instead of 3.x, you can be more memory-efficient by using xrange(), changing the above code to: chunks = [data[x:x+100] for x in xrange(0, len(data), 100)]