“%f” is the (or at least one) correct format for a double. There is no format for a float, because if you attempt to pass a float to printf, it’ll be promoted to double before printf receives it1. “%lf” is also acceptable under the current standard — the l is specified as having no effect … Read more
Put an l (lowercased letter L) directly before the specifier. unsigned long n; long m; printf(“%lu %ld”, n, m);
There is no format specifier for bool types. However, since any integral type shorter than int is promoted to int when passed down to printf()‘s variadic arguments, you can use %d: bool x = true; printf(“%d\n”, x); // prints 1 But why not: printf(x ? “true” : “false”); or, better: printf(“%s”, x ? “true” : … Read more
The stdout stream is line buffered by default, so will only display what’s in the buffer after it reaches a newline (or when it’s told to). You have a few options to print immediately: Print to stderrinstead using fprintf (stderr is unbuffered by default): fprintf(stderr, “I will be printed immediately”); Flush stdout whenever you need … Read more
Current JavaScript From ES6 on you could use template strings: let soMany = 10; console.log(`This is ${soMany} times easier!`); // “This is 10 times easier! See Kim’s answer below for details. Older answer Try sprintf() for JavaScript. If you really want to do a simple format method on your own, don’t do the replacements successively … Read more